Problem doing induction question

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SUMMARY

The discussion focuses on proving the formula for the sum of cubes of the first n even numbers using mathematical induction: 2³ + 4³ + 6³ + ... + (2n)³ = 2n²(n+1)² for all n ≥ 1. The user successfully verifies the base case for n=1 and assumes the induction hypothesis for n=k. However, confusion arises during the transition to n=k+1, where the user mistakenly includes an extra term. The error is identified as incorrectly handling the term 2³, which leads to a miscalculation in the proof.

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Homework Statement


Prove the following result using mathematical induction:
2³+4³+6³+...+(2n)³=2n²(n+1)² for all n>or=1


Homework Equations





The Attempt at a Solution


n=1:
(2(1))³=2(1)²(2)³
8=8

Assume n=k
2³+4³+6³+...+(2k)³=2k²(k+1)²

n=k+1
2³+4³+6³+...+(2k)³+(2(k+1))³=2(k+1)²(k+2)²
Using assumption
2k²(k+1)²+(2(k+1))³=2(k+1)²(k+2)²
Divide by 2(k+1)²
k²+k+1=(k+2)²
k²+k+1=k²+4k+4

I can't understand where I've gone wrong.
Any help would be greatly appreciated.
 
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Figured it out the second I put it up. Removed a 2³ as a 2.
 
sbsbsbsb said:

Homework Statement


Prove the following result using mathematical induction:
2³+4³+6³+...+(2n)³=2n²(n+1)² for all n>or=1

Homework Equations



The Attempt at a Solution


n=1:
(2(1))³=2(1)²(2)³
8=8

Assume n=k
2³+4³+6³+...+(2k)³=2k²(k+1)²

n=k+1
2³+4³+6³+...+(2k)³+(2(k+1))³=2(k+1)²(k+2)²
Using assumption
The following line looks as if you are assuming the very thing you are to prove.
2k²(k+1)²+(2(k+1))³=2(k+1)²(k+2)²
Divide by 2(k+1)²
k²+k+1=(k+2)²
k²+k+1=k²+4k+4

I can't understand where I've gone wrong.
Any help would be greatly appreciated.
 

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