Problem of the Week #23 - November 5th, 2012

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SUMMARY

The problem presented involves a bijective continuous function \( f: X \rightarrow Y \) between topological spaces \( X \) and \( Y \). It is established that if \( X \) is compact and \( Y \) is Hausdorff, then \( f \) is a homeomorphism. This conclusion follows from the properties of compactness and the Hausdorff condition, which ensure that the inverse function \( f^{-1} \) is also continuous, thus confirming that \( f \) meets the criteria for a homeomorphism.

PREREQUISITES
  • Understanding of bijective functions in topology
  • Knowledge of compact spaces in topology
  • Familiarity with Hausdorff spaces
  • Concept of homeomorphisms in topology
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  • Study the properties of compact spaces in topology
  • Learn about Hausdorff spaces and their significance
  • Explore the definition and examples of homeomorphisms
  • Investigate the implications of continuous functions in topological spaces
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Mathematicians, students of topology, and anyone interested in understanding the relationships between compact and Hausdorff spaces in the context of homeomorphisms.

Chris L T521
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Here's this week's problem.

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Problem: Let $f:X\rightarrow Y$ be a bijective continuous function between topological spaces $X$ and $Y$. If $X$ is compact and $Y$ is Hausdorff, show that $f$ is a homeomorphism.

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No one answered this week's question. Here's my solution.

Proof: All we really need to do is justify that $f^{-1}:Y\rightarrow X$ is continuous; to do this, we need to show that the images of closed sets in $X$ are closed in $Y$. Let $A\subseteq X$ be a closed set in $X$. Since $X$ is compact, it follows that $A$ is compact (since a set is compact iff it's closed and bounded). The image of a compact set is compact, so it follows that $f(A)$ is compact. Since compact sets in a Hausdorff space are closed, it now follows that $f(A)$ is closed in $Y$ and thus $f^{-1}$ is continuous. Q.E.D.
 

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