MHB Problem of the Week #301 - June 28, 2022

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The problem states that for a holomorphic function \( f \) in an open subset \( \Omega \subset \mathbb{C} \), the integral \( \oint_{\Gamma} \overline{f(z)}f’(z)\, dz \) over any closed contour \( \Gamma \) in \( \Omega \) is purely imaginary. The discussion includes a solution to this problem, demonstrating the application of properties of holomorphic functions and contour integration. Key points involve the use of Cauchy's integral theorem and the relationship between \( f \) and its conjugate. The conclusion emphasizes that the integral's imaginary nature stems from the holomorphicity of \( f \) and the behavior of complex conjugates in integration. This highlights important concepts in complex analysis.
Euge
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Here is this week's problem!

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Prove that if $f$ is holomorphic in an open subset $\Omega\subset \mathbb{C}$, then for all closed countours $\Gamma$ in $\Omega$, the integral $\oint_{\Gamma} \overline{f(z)}f’(z)\, dz$ is purely imaginary.
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Here is my solution.

The differential form ##\overline{f(z)}f'(z)\, dz = \overline{f(z)}\,df(z)##, so ##2\operatorname{Re}(\overline{f(z)}f'(z)\, dz) = \overline{f}\, df + f\, d\overline{f} = d(f\overline{f})##, an exact differential. Therefore $$2\operatorname{Re} \oint_\Gamma \overline{f(z)}f'(z)\, dz = \oint_\Gamma 2\operatorname{Re}(\overline{f(z)}f'(z)\, dz) = 0$$ and the result follows.
 
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