MHB Problem on finding least number

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To determine how many times six bells ring together in 30 minutes, the least common multiple (LCM) of their ringing intervals (2, 4, 6, 8, 10, and 12 seconds) must be calculated. The LCM will provide the interval in seconds at which all bells ring simultaneously. Once the LCM is found, the number of these intervals within 30 minutes can be calculated. This process involves basic arithmetic and understanding of LCM. The solution will reveal the total number of times the bells ring together during that period.
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Help need to solve math homework problem

Six bells start ringing together and ring at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes, how many times do they ring together?

Thanks
 
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So how many intervals of 2 seconds are there in 30 mins?

How many intervals of 4 seconds?

How many intervals of 6? etc...
 
burgess said:
Help need to solve math homework problem

Six bells start ringing together and ring at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes, how many times do they ring together?

Thanks
You need to find the least common multiple of 2, 4, 6, 8, 10 and 12. That will give you the interval (measured in seconds) between times when they all ring together. You then have to find how many of those intervals there are in 30 minutes.
 
Opalg said:
You need to find the least common multiple of 2, 4, 6, 8, 10 and 12. That will give you the interval (measured in seconds) between times when they all ring together. You then have to find how many of those intervals there are in 30 minutes.

Thanks for your answer
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...
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