MHB Problem on finding least number

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To determine how many times six bells ring together in 30 minutes, the least common multiple (LCM) of their ringing intervals (2, 4, 6, 8, 10, and 12 seconds) must be calculated. The LCM will provide the interval in seconds at which all bells ring simultaneously. Once the LCM is found, the number of these intervals within 30 minutes can be calculated. This process involves basic arithmetic and understanding of LCM. The solution will reveal the total number of times the bells ring together during that period.
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Help need to solve math homework problem

Six bells start ringing together and ring at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes, how many times do they ring together?

Thanks
 
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So how many intervals of 2 seconds are there in 30 mins?

How many intervals of 4 seconds?

How many intervals of 6? etc...
 
burgess said:
Help need to solve math homework problem

Six bells start ringing together and ring at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes, how many times do they ring together?

Thanks
You need to find the least common multiple of 2, 4, 6, 8, 10 and 12. That will give you the interval (measured in seconds) between times when they all ring together. You then have to find how many of those intervals there are in 30 minutes.
 
Opalg said:
You need to find the least common multiple of 2, 4, 6, 8, 10 and 12. That will give you the interval (measured in seconds) between times when they all ring together. You then have to find how many of those intervals there are in 30 minutes.

Thanks for your answer
 
I have been insisting to my statistics students that for probabilities, the rule is the number of significant figures is the number of digits past the leading zeros or leading nines. For example to give 4 significant figures for a probability: 0.000001234 and 0.99999991234 are the correct number of decimal places. That way the complementary probability can also be given to the same significant figures ( 0.999998766 and 0.00000008766 respectively). More generally if you have a value that...

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