Problem simplifying an equation

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mr.t
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Homework Statement


What is the steps between the two equations?


Homework Equations


[tex]P = a^{2}P+b^{2}P^{2}/(P+1) \Rightarrow P^{2}-(a^{2}+b^{2}-1)P-b^{2} = 0[/tex]

Thanks!
 
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mr.t said:
What is the steps between the two equations?

[tex]P = a^{2}P+b^{2}P^{2}/(P+1) \Rightarrow P^{2}-(a^{2}+b^{2}-1)P-b^{2} = 0[/tex]

Thanks!

Hi mr.t! :smile:

i] put the a2P on the left

ii] multiply both sides by (P + 1) :smile:
 
Hello Tiny-tim!
Putting the [tex]a^{2}P[/tex] to the left and multiply both sides with (P+1) gives:

[tex](P+1)(P-a^{2}P) = b^{2}P^{2} \Rightarrow[/tex]
[tex]\Rightarrow P^{2}-a^{2}P^{2}+P-a^{2}P-b^{2}P^{2} = 0 \Rightarrow[/tex]
[tex]\Rightarrow P^{2}(1-a^{2}-b^{2})+P(1-a^{2}) = 0[/tex]

But I still can't come to the final solution? :S
 
I don't think the two steps are equivalent. Let b=0, then a^2=1 if [tex]P \neq 0[/tex]. Substituting these into the second equation, we have a^2 = 1 only if [tex]P = 0[/tex]
 
It could be an error in the solution then no fun try to learn stuff when you end up spending your time figuring out the imposible...

thanks for your time anyway!