Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Probobalistic interpretation of a PDE

  1. Mar 1, 2013 #1

    kai_sikorski

    User Avatar
    Gold Member

    Consider the following PDE. A lot of this is from "Numerical Analysis of an Elliptic-Parabolic Partial Differential Equation" by J. Franklin and E. Rodemich.

    [itex]\frac{1}{2} \frac{\partial^2 T}{\partial y^2} + y \frac{\partial T}{\partial x} = -1[/itex]

    With [itex]|x|<1, |y| < \infty[/itex] and we require T(1,y)=0 for y>0 and T(-1,y)=0 for y<0, and T(x,y) → 0 as |y| → ∞.

    The solution T(x,y) is related to a randomly accelerated particle whose position ζ(t) satisfies the SDE ζ''(t) = w(t), where w(t) is white Gaussian noise. If the initial position and velocity are ζ(0) = x and ζ'(0)=y, where |x|<1, then T(x,y) is the expected value of the first time at which the sosition ζ(t) equals ±1.

    I'm wondering if there is a similar probabilistic interpretation of a similar problem but with an x dependent forcing.

    [itex]\frac{1}{2} \frac{\partial^2 T}{\partial y^2} + y \frac{\partial T}{\partial x} = -G(x)[/itex]

    Intuitively it seems that maybe I can integrate the right hand side along the path of the random particle, but I'm not sure if this is right. This seems similar in flavor to the Feynman-Kac theorem, but I haven't been able to find a formulation of that theorem that quite works for what I want.
     
  2. jcsd
  3. Mar 2, 2013 #2

    kai_sikorski

    User Avatar
    Gold Member

    Think I found what I need in Grigorius stochastic calculus book, it looks like my intuition was right.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Probobalistic interpretation of a PDE
  1. Prerequisites for PDE ? (Replies: 10)

  2. Solutions to this PDE? (Replies: 4)

  3. Tough pde (Replies: 21)

  4. Linearity of PDE (Replies: 4)

Loading...