Processing 0.25% Silver Ore to Obtain 2 Pounds

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SUMMARY

The discussion focuses on calculating the volume of 0.25% silver ore required to yield 2 pounds of silver, given the ore's density of 7.0 g/cm³. The correct calculation reveals that 52,000 cm³ of ore must be processed to obtain the desired amount of silver, correcting a common mistake of misinterpreting the percentage as a decimal. The error identified was not converting 0.25% to its decimal form (0.0025), which led to an incorrect volume estimate of 520 cm³.

PREREQUISITES
  • Understanding of percentage conversion to decimal form
  • Basic knowledge of density and volume calculations
  • Familiarity with mass-to-volume conversions (e.g., pounds to grams)
  • Concept of 100% efficiency in processing
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  • Study the conversion of percentages to decimals in mathematical calculations
  • Learn about density and its role in calculating volume from mass
  • Research mass-to-volume conversion techniques, specifically for metals
  • Explore efficiency concepts in material processing and extraction methods
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Students in chemistry or materials science, metallurgists, and anyone involved in the extraction of metals from ores.

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How many cubic centimeters of ore 0.25% by mass silver must be processed to obtain 2.0 pounds of silver? The density of the ore is 7.0 g/cm cubed. cm cubed; 1.00 pound=454 g. Assume that the process is 100% efficient.

I get the answer of 520 but the answer is 52000 and i don't understand why I am so off. Can someone help me please i would really appreciate it.


Thank you :smile:
 
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This is just a guess, but since your answer is off by a factor of 100, I bet the problem came when you did not divide .25% by 100 in your calculations (.25% = .0025 in decimal form).
 

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