Product at anode of the electrolysis of MgBr2

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SUMMARY

The product at the anode during the electrolysis of magnesium bromide (MgBr2) is bromine (Br2) instead of oxygen (O2) due to the kinetics of the reactions involved. The standard electrode potential (EΘ) for the oxidation of hydroxide ions (OH-) is -0.40 V, while that of bromide ions (Br-) is -1.07 V. Although oxygen evolution is thermodynamically favored, it occurs slowly, requiring an overpotential that leads to the production of Br2 at higher voltages. This phenomenon is also observed in brine solutions, where chlorine can be detected despite oxygen being the expected product.

PREREQUISITES
  • Understanding of electrolysis principles
  • Knowledge of standard electrode potentials
  • Familiarity with reaction kinetics
  • Basic chemistry of halides and their oxidation states
NEXT STEPS
  • Research the kinetics of oxygen evolution reactions in electrolysis
  • Study the electrochemical series and standard electrode potentials
  • Explore the effects of overpotential on electrolysis products
  • Investigate other exceptions in electrolysis, such as in brine solutions
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Chemistry students, electrochemists, and professionals involved in industrial electrolysis processes will benefit from this discussion.

Janiceleong26
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1. Homework Statement
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Why is the product at anode Br2 for MgBr2? Instead of O2?

Homework Equations

The Attempt at a Solution


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The EΘ value for the oxidation of OH- is -0.40 V,
And that of Br- is -1.07V
And so, shouldn't oxidation of OH- be easier? And hence, O2 is formed at the anode?
 
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If memory serves me well, the explanation lies in the kinetics. In general yes, oxygen should be formed. In practice oxygen evolution is quite slow, so you need an overpotential to speed it up, which moves you into the voltages where Br2 is produced. It is the same with brine solutions, where you can easily smell chlorine despite the fact oxygen should evolve first.
 
Borek said:
If memory serves me well, the explanation lies in the kinetics. In general yes, oxygen should be formed. In practice oxygen evolution is quite slow, so you need an overpotential to speed it up, which moves you into the voltages where Br2 is produced. It is the same with brine solutions, where you can easily smell chlorine despite the fact oxygen should evolve first.
Woah I see.. How am suppose to know this during the exam ?
Anyways, thanks. Are there any other exceptions other than brine and MgBr2?
 
I believe oxygen in general evolves slowly, so whenever it is one of possible products, other things can be produced as well at higher potentials.

Note: I am not entirely sure about this explanation, take it with a grain of salt.
 
Borek said:
I believe oxygen in general evolves slowly, so whenever it is one of possible products, other things can be produced as well at higher potentials.

Note: I am not entirely sure about this explanation, take it with a grain of salt.
Alright, thanks!
 
Borek said:
If memory serves me well, the explanation lies in the kinetics. In general yes, oxygen should be formed. In practice oxygen evolution is quite slow, so you need an overpotential to speed it up, which moves you into the voltages where Br2 is produced. It is the same with brine solutions, where you can easily smell chlorine despite the fact oxygen should evolve first.

Thank you borek
 
Borek said:
If memory serves me well, the explanation lies in the kinetics. In general yes, oxygen should be formed. In practice oxygen evolution is quite slow, so you need an overpotential to speed it up, which moves you into the voltages where Br2 is produced. It is the same with brine solutions, where you can easily smell chlorine despite the fact oxygen should evolve first.
Thank you borek
 

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