Understanding Electron Flow in EMF Cells: Anode to Cathode or Cathode to Anode?

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Discussion Overview

The discussion revolves around the flow of electrons in an electrochemical cell, specifically the Zn | Zn2+ (1M) || Cu2+ (1M) | Cu cell, under varying external potentials. Participants explore the implications of these conditions on electron flow direction, addressing both theoretical and practical aspects of electrochemistry.

Discussion Character

  • Homework-related
  • Debate/contested
  • Technical explanation

Main Points Raised

  • One participant states that when the external potential (Eext) is less than 1.1V, electrons flow from anode to cathode, and when Eext is greater than 1.1V, they flow from cathode to anode, suggesting option 1 is correct.
  • Another participant argues that the definitions of anode and cathode dictate that electrons always flow from the anode to the cathode, regardless of the external current direction, indicating a potential misunderstanding in the question's framing.
  • A third participant echoes the previous point, reinforcing the idea that the roles of anode and cathode switch when the battery is reversed, but the electron flow remains consistent from anode to cathode externally.
  • A later reply emphasizes the importance of reduction potentials, stating that electrons flow from the more negative to the more positive potential, and suggests considering the effects of ion concentrations on cell voltage.

Areas of Agreement / Disagreement

Participants express differing views on the interpretation of electron flow in relation to the definitions of anode and cathode, with no consensus reached on the correct answer to the posed question. The discussion remains unresolved regarding the implications of external potential on electron flow direction.

Contextual Notes

Participants reference the concept of reduction potentials and the effects of ion concentrations, indicating that the discussion may depend on specific definitions and assumptions about electrochemical cells.

Raghav Gupta
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Homework Statement


A variable , opposite external potential ## E_{ext} ## is applied to the cell Zn | Zn2+ (1M) || Cu2+ (1M) | Cu, of potential 1.1V . When Eext < 1.1 V and Eext > 1.1V , respectively electrons flow from :
1. anode to cathode and cathode to anode
2. cathode to anode and anode to cathode
3. cathode to anode in both cases
4. anode to cathode in both cases

Homework Equations



NA

The Attempt at a Solution


At anode oxidation happens and at cathode reduction.
So electrons are moving from anode to cathode when Eext < 1.1 V and cathode to anode when Eext > 1.1 V
So option 1 is looking correct.
In answer key option 4 that is anode to cathode in both cases is given.
Why?
 
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My guess is this is almost a "trick" question,
The anode is defined as the electrode where electrons leave a cell and the cathode where electrons enter a cell. So no matter which way the current flows, external to the cell electrons always flow from anode to cathode.
When you switch the battery, you switch the names of the electrodes.
 
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Merlin3189 said:
My guess is this is almost a "trick" question,
The anode is defined as the electrode where electrons leave a cell and the cathode where electrons enter a cell. So no matter which way the current flows, external to the cell electrons always flow from anode to cathode.
When you switch the battery, you switch the names of the electrodes.
Thanks, got the tricky part.
 
Look at a table of Reduction Potentials (here's one for quick reference: http://chemunlimited.com/Table of Reduction Potentials.pdf ), in all cases electrons flow from the more negative reduction potential to the more positive reduction potential ... ALWAYS. Choose any two half reactions and note the Eo-values. The more negative value is the anode (site of oxidation) and the more positive value cathode (site of reduction). I might suggest studying how the respective ion concentrations in each half cell affect the voltage of the Galvanic/Voltaic Process. That is, what voltage does the cell have if [reducing agent ion] < [oxidizing agent ions] and visa versa. If [oxidizing agent ions] = [reducing agent ions] what is the cell voltage? Happy charging... :smile:
 

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