1. The problem statement, all variables and given/known data Why is the product at anode Br2 for MgBr2? Instead of O2? 2. Relevant equations 3. The attempt at a solution The EΘ value for the oxidation of OH- is -0.40 V, And that of Br- is -1.07V And so, shouldn't oxidation of OH- be easier? And hence, O2 is formed at the anode?