Product at anode of the electrolysis of MgBr2

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Discussion Overview

The discussion centers on the electrolysis of magnesium bromide (MgBr2) and the products formed at the anode, specifically questioning why bromine (Br2) is produced instead of oxygen (O2). The scope includes theoretical considerations of electrochemical reactions and kinetics involved in the process.

Discussion Character

  • Homework-related
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant notes that the standard electrode potential (EΘ) values suggest that oxidation of hydroxide ions (OH-) is thermodynamically more favorable than that of bromide ions (Br-), which raises the question of why Br2 is produced.
  • Another participant suggests that the kinetics of the reactions play a significant role, indicating that while oxygen should theoretically evolve, its production is slow and requires an overpotential, leading to the formation of Br2 at practical voltages.
  • Several participants express uncertainty about the kinetics and the conditions under which different products may form, with one participant asking for clarification on other exceptions beyond brine and MgBr2.
  • Repetitive assertions about the slow evolution of oxygen and the potential for other products to form at higher potentials are made, with participants advising caution regarding the reliability of these explanations.

Areas of Agreement / Disagreement

Participants generally agree that the kinetics of the reactions influence the products formed during electrolysis, but there is no consensus on the details of these processes or the implications for other scenarios.

Contextual Notes

There are unresolved aspects regarding the specific conditions that lead to the production of Br2 over O2, including the role of overpotential and the exact mechanisms at play in the electrolysis of MgBr2.

Janiceleong26
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1. Homework Statement
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Why is the product at anode Br2 for MgBr2? Instead of O2?

Homework Equations

The Attempt at a Solution


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[/B]

The EΘ value for the oxidation of OH- is -0.40 V,
And that of Br- is -1.07V
And so, shouldn't oxidation of OH- be easier? And hence, O2 is formed at the anode?
 
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If memory serves me well, the explanation lies in the kinetics. In general yes, oxygen should be formed. In practice oxygen evolution is quite slow, so you need an overpotential to speed it up, which moves you into the voltages where Br2 is produced. It is the same with brine solutions, where you can easily smell chlorine despite the fact oxygen should evolve first.
 
Borek said:
If memory serves me well, the explanation lies in the kinetics. In general yes, oxygen should be formed. In practice oxygen evolution is quite slow, so you need an overpotential to speed it up, which moves you into the voltages where Br2 is produced. It is the same with brine solutions, where you can easily smell chlorine despite the fact oxygen should evolve first.
Woah I see.. How am suppose to know this during the exam ?
Anyways, thanks. Are there any other exceptions other than brine and MgBr2?
 
I believe oxygen in general evolves slowly, so whenever it is one of possible products, other things can be produced as well at higher potentials.

Note: I am not entirely sure about this explanation, take it with a grain of salt.
 
Borek said:
I believe oxygen in general evolves slowly, so whenever it is one of possible products, other things can be produced as well at higher potentials.

Note: I am not entirely sure about this explanation, take it with a grain of salt.
Alright, thanks!
 
Borek said:
If memory serves me well, the explanation lies in the kinetics. In general yes, oxygen should be formed. In practice oxygen evolution is quite slow, so you need an overpotential to speed it up, which moves you into the voltages where Br2 is produced. It is the same with brine solutions, where you can easily smell chlorine despite the fact oxygen should evolve first.

Thank you borek
 
Borek said:
If memory serves me well, the explanation lies in the kinetics. In general yes, oxygen should be formed. In practice oxygen evolution is quite slow, so you need an overpotential to speed it up, which moves you into the voltages where Br2 is produced. It is the same with brine solutions, where you can easily smell chlorine despite the fact oxygen should evolve first.
Thank you borek
 

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