Projectile Problem Help: Find Maximum Distance and Collision Point - g=10m/s2

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The discussion focuses on solving a projectile motion problem involving two objects thrown from different heights and angles. The first object is launched horizontally from a 20m high tower (AB) with a velocity of 10m/s, while the second object is thrown from a 30m high tower (CD) at a 60-degree angle below the horizontal, also with a velocity of 10m/s. The equations of motion used are x=vtcos(θ) and y=vtsin(θ)-½gt², with gravitational acceleration set at g=10m/s². The goal is to determine the distance 'd' between the towers and the collision point of the two objects before they hit the ground.

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1. A ship is approaching a cliff of height 105m above sea level. gun fited on ship can fire shots with 110m/s. Find the maximum distance frm the foot of cliff from where the gun can hit an object on the top of cliff. g=10m/s2

2. 2towers AB and CD are situated a distance 'd' apart. AB is 20m high and CD is 30 m high frm ground. an object of mass 'm' is thrown from the top of AB horizontally with a velocity of 10m/s towards CD. Simultaneously another object of mass '2m' is thrown from top of CD at an angle 60degree below horizontal towards AB with the same magnitude of intial velocity as that of the first object. 2 objects move in the same vertical plane, collide in mid air and stick to each other.
i) find 'd'
ii) find position where the objects hit ground
 
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1. Start with these equations:

[tex]x=vtcos(\theta)[/tex]
[tex]y=vtsin(\theta)-\frac{1}{2}gt^2[/tex]

You will need to eliminate [tex]t[/tex] between the two equations.
 

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