Projections onto a plane and parallel to a vector

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SUMMARY

The discussion focuses on the mathematical concept of projections in linear algebra, specifically projecting onto a plane defined by the equation 2x1 - 3x2 + x3 = 0, parallel to the vector v=(2,1,0). The linear application for this projection is defined as P(x1,x2,x3) = (-3x1 + 6x2 - 2x3, -2x1 + 4x2 - x3, x3). The user seeks clarity on how this projection is derived and the meaning of "parallel to a vector" in this context.

PREREQUISITES
  • Understanding of linear algebra concepts, particularly projections.
  • Familiarity with vector equations and their geometric interpretations.
  • Knowledge of linear transformations and their representations.
  • Basic skills in solving systems of equations in R^3.
NEXT STEPS
  • Study the derivation of projections in linear algebra, focusing on projections onto planes.
  • Learn about the geometric interpretation of vectors and planes in R^3.
  • Explore linear transformations and their matrix representations in detail.
  • Investigate the concept of vector parallelism and its implications in projections.
USEFUL FOR

Students preparing for linear algebra exams, particularly those in physics or engineering programs, and anyone seeking to deepen their understanding of vector projections and linear transformations.

Blacky&Imy
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Hi. I'm preparing the Linear algebra 1 Exam for the first year of
Physics University. I find very difficult to understand projections.
Here's an example:
Consider the projection P: R^3 --> R^3 onto the plane U of equation
2x1 - 3x2 + x3 = 0 and parallel (the projection) to the vector v=(2,1,0).

This is to say, P is the linear application defined as follows:

P(x1,x2,x3) = ( -3x1 + 6x2 - 2x3 , -2x1 + 4x2 - x3 , x3 )

I can't see why P is defined this way, how they got it, so I would
appreciate if you could show me the passages step-by-step. In general, I can't understand how to define a projection, given the vector and the plane. Also, I'd
like to understand what does "parallel to a vector" means in this case.

Thanks a lot.
 
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