Proof by Induction - Inequalities

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Homework Help Overview

The discussion revolves around proving an inequality using mathematical induction. Participants are examining the validity of an approach to the proof and the transformations involved in the inequality.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants are questioning the correctness of the original poster's method and suggesting starting from the base case. There are discussions about the transformations of the inequality and alternative perspectives on approaching the proof.

Discussion Status

Some participants have offered guidance on how to approach the proof, highlighting potential errors in the original poster's reasoning. Multiple interpretations of the inequality and its transformations are being explored, but there is no explicit consensus on the correct method yet.

Contextual Notes

There is a reference to an attachment that presumably contains the specific inequality to be proven, which is not visible in the discussion. Participants are also addressing the implications of certain assumptions related to the variables involved in the inequality.

odolwa99
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Homework Statement



Prove by induction that: (Please see attachment)

Homework Equations



The Attempt at a Solution



Can someone please confirm if I have worked the question out correctly. Many thanks.
 

Attachments

  • math (2).jpg
    math (2).jpg
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Your method is not correct. Start from the inequality you supposed to be true (for n=k) and transform it till you arrive to the desired form. You started from the case n=k+1 and went backwards. That is wrong. ehild
 
It might help you to note that
[tex]\frac{1}{(1+r)^n}\le \frac{1}{1+ rn}[/tex]
is exactly the same as
[tex]1+ rn\le (1+ r)^n[/tex]
so you don't have to worry about the fractions.
 
the second line from the end looks incorrect.
[itex]\frac{1}{k\cdot r^2} \le 0 \Leftrightarrow k<0, r\ne 0[/itex]
why won't you try to attack it from another aspect. for example,
[itex]p_1>p2>0 \rightarrow \frac{1}{p_2}>\frac{1}{p_1}[/itex]
 
Thank you for the help guys. I genuinely appreciate it.
 

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