Proper Motion of Stars: Solving Daniel's Calculation Problem

Click For Summary

Homework Help Overview

The discussion revolves around the calculation of the proper motion of stars, specifically focusing on converting velocities into Cartesian coordinates. The original poster, Daniel, presents a set of velocities and angles, expressing confusion over discrepancies between his results and those found in a reference.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Daniel attempts to calculate Cartesian velocities using given radial and tangential velocities, but finds inconsistencies with expected results. He questions whether he has correctly converted angles from hours to degrees and whether his calculations are accurate.

Discussion Status

Some participants provide guidance on the conversion of angles and suggest checking calculations. Daniel acknowledges a mistake in his angle conversion after receiving feedback, indicating a shift towards resolving his confusion.

Contextual Notes

There is a mention of using Excel for calculations, and the discussion includes specific values for velocities and angles that are critical to the problem. The original poster's results differ from those in the reference material, prompting a review of assumptions and calculations.

Daniel P
Messages
3
Reaction score
0
Hi

I have a question about "proper motion of stars".
At this page (http://www.astronexus.com/a-a/motions-long-term) there are a lot of examples how you can measuring the proper motion of stars.

But at "Point 4 - Turn these velocities into Cartesian velocities" i have some different results.

vR = -5.19 Km/sec
vTA = -58.3 Km/sec
vTD = -106.6 Km/sec
α = 14.2612
δ = 19.1873

===========================================================================
should!

vx = ( vR * cos δ * cos α ) - (vTA*sin α ) - (vTD * sin δ * cos α ) = -57.7 Km/sec
vy = ( vR * cos δ * sin α ) + (vTA * cos α ) - (vTD * sin δ sin α ) = +31.5 Km/sec
vz = vR * sin δ + vTD* cos δ = -102.3 Km/sec

===========================================================================

My results: vx = +54.1, xy = +37.5 and xz = -102.4
You can see the results one and two don't agree with my calculation, the result three agrees (depents on the accuracy of "my" data!)

Can anybody help me, please?

Thank you very much,
DANIEL
 
Last edited:
Physics news on Phys.org
Did you see that α is in hours, not degrees? Did you convert it to degrees before taking the sin and cos?
 
Hi

now i have seen that i must convert α = 14.2612 Hours in degrees (=213.915°)! So far so good!

but if i calculate Vx = -5.19*COS(19.1873)*COS(213.915)-(-58.34*SIN(213.915))-(-106.6*SIN(19.1873)*COS(213.915)) = +45.7 instead -57.7 Km/sec.
and if i calculate Vy = -5.19*COS(19.1873)*SIN(213.915)+(-58.34*COS(213.915)-(-106.6*SIN(19.1873)*SIN(213.915)) = -47.7 instead +31.5 Km/sec

i calculate it with Excel!

query: http://www.astronexus.com/a-a/motions-long-term

thank you again, phyzguy!
 
You must have made a mistake. See below:
Code:
from pylab import *
alpha = 14.2612 * 15.0 * pi / 180.0
delta = 19.1873 * pi / 180.0
vR = -5.0 
vTA = -58.3 
vTD = -106.6 
vx = (vR * cos(delta) * cos(alpha)) - (vTA * sin(alpha)) - (vTD * sin(delta) * cos(alpha))
vy = (vR * cos(delta) * sin(alpha)) + (vTA * cos(alpha)) - (vTD * sin(delta) * sin(alpha))
vz = vR * sin(delta) + vTD * cos(delta)
print vx, vy, vz

-57.6862773004 31.464877787 -102.321575814
 
Ohh ok now i have the right result! i forgot the ("Pi/180"):eek:
Tthank you very much!
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
12K