Prove an Identity in Boolean Algebra: Help Needed!

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SUMMARY

The forum discussion centers on proving the Boolean algebra identity (A + C)(¬A + B) = AB + ¬A·C. The user initially expanded the left-hand side (LHS) and encountered an extra term B·C. A participant suggested using the distribution rule and hinted at multiplying by (A + ¬A) or (C + ¬C) to simplify the proof. This approach is essential for resolving the identity correctly.

PREREQUISITES
  • Understanding of Boolean algebra concepts
  • Familiarity with distribution and simplification rules in Boolean expressions
  • Knowledge of identity laws in Boolean algebra
  • Ability to manipulate logical expressions
NEXT STEPS
  • Study the distribution rule in Boolean algebra
  • Learn about identity laws, specifically A + ¬A = 1
  • Explore techniques for simplifying Boolean expressions
  • Practice proving other Boolean identities for deeper understanding
USEFUL FOR

This discussion is beneficial for students of computer science, electrical engineering, and anyone studying digital logic design who seeks to strengthen their understanding of Boolean algebra and identity proofs.

jksdvb8
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May seem easy, I can't do it though...

I'm given an identity to prove:-

(A + C).(notA + B) = A.B + notA.C

I've started with LHS, multiplied out and ended up with an extra B.C. I think this has something to do with the distribution rule but I don't know how to work it through

Any help greatly appreciated

JK
 
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welcome to pf!

hi jksdvb8! welcome to pf! :smile:
jksdvb8 said:
I've started with LHS, multiplied out and ended up with an extra B.C.

so you need to prove that B.C is contained in A.B + notA.C

hint: multiply something by either (A + notA) or (C + notC) :wink:
 

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