Prove Heron's Formula (Trigonometry)

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SUMMARY

Heron's Formula states that the area K of a triangle with sides a, b, and c is given by K = √(s(s-a)(s-b)(s-c)), where s = (a+b+c)/2 is the semiperimeter. The discussion revolves around proving this formula using the area formula K = (1/2)bc sin A, where A is the angle opposite side a. Participants share their attempts at deriving the formula, emphasizing the use of trigonometric identities and the Law of Cosines to simplify the expressions involved.

PREREQUISITES
  • Understanding of Heron's Formula and its components
  • Knowledge of trigonometric identities, specifically sin²A + cos²A = 1
  • Familiarity with the Law of Cosines
  • Basic algebraic manipulation skills for simplifying expressions
NEXT STEPS
  • Study the derivation of Heron's Formula in detail
  • Learn about the Law of Cosines and its applications in triangle geometry
  • Explore trigonometric identities and their proofs
  • Practice solving triangle area problems using different methods
USEFUL FOR

Students studying trigonometry, mathematics educators, and anyone interested in geometric proofs and triangle area calculations.

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Homework Statement



If a, b, c are the lengths of the sides of a triangle, then the area K of the triangle is given by K=\sqrt{s(s-a)(s-b)(s-c)}, where s=\frac{1}{2}(a+b+c). The number s is called the semiperimeter. Prove Heron's Formula. Hint: Use the area formula K=\frac{1}{2}bc\sin\phi.

sinphi should be sinA. it wouldn't let me use sinA.

The Attempt at a Solution



Absolute torture if you ask me! I need help getting on the right track, any help is appreciated.

Ignore everything from the triangle and down, that's a different problem.

http://img206.imageshack.us/img206/697/53149485pi4.jpg​
 
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my way:
K=whatever
K^2=whatever without sqrt

K^2 = that sin theta area^2

and using identidy sin^2 = 1-cos^2 in above

and cosine law, and some simplication, you would eventually reach somewhere like
-a^4+6a^3+3a^2...

and now just expand that herione thing

lol >(evil smile)<
 
rootX said:
my way:
K=whatever
K^2=whatever without sqrt

K^2 = that sin theta area^2

and using identidy sin^2 = 1-cos^2 in above

and cosine law, and some simplication, you would eventually reach somewhere like
-a^4+6a^3+3a^2...

and now just expand that herione thing

lol >(evil smile)<
lol ... i don't follow!
 
you didn't square the equation in the starting, but I did..
 
rootX said:
you didn't square the equation in the starting, but I did..
ok let me try it that way.
 

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