MHB Prove Inequality $(a,b,c\geq1)$

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$given :\,\,$ $a,b,c\geq1$

$prove:$

$(1+a)(1+b)(1+c)\geq 2(1+a+b+c)$
 
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Here is my solution.

$$(1+a)(1+b)(1+c) = 1 + a + b + c + ab + bc + ca + abc $$

and since $a,b,c \ge 1$, then $ab + bc + ca \ge a + b + c $ and $abc \ge 1$; the result now follows.
 

Thread 'Area of Overlapping Squares'

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