Prove No Solution for Equation $y^3=1+2^{2^x}$ in Natural Numbers

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SUMMARY

The equation \( y^3 = 1 + 2^{2^x} \) has been proven to have no solutions in natural numbers. The discussion highlights the contributions of member greg1313, who provided a definitive solution to the problem. The proof relies on properties of powers of two and modular arithmetic, demonstrating that the left-hand side cannot equal the right-hand side for any natural number values of \( y \) and \( x \).

PREREQUISITES
  • Understanding of modular arithmetic
  • Familiarity with properties of powers of two
  • Knowledge of natural number properties
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study modular arithmetic applications in number theory
  • Explore properties of exponential functions, particularly \( 2^{2^x} \)
  • Investigate proofs of non-existence for Diophantine equations
  • Learn about the implications of Fermat's Last Theorem on similar equations
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Mathematicians, number theorists, and students interested in algebraic equations and their proofs will benefit from this discussion.

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Prove that the equation $\large y^3=1+2^{2^x}$has no solution in natural numbers.


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Congratulations to the following member for his correct solution:

1. greg1313

Solution from greg1313:

Proof by induction.

Base case: $$1^3-1=0\ne2^{2^x}$$

Inductive step: $$(n+1)^3-1=n(n^2+3n+3)=2^{2^x}$$$n^2+3n+3$ is odd, so it cannot divide $2^{2^x}$.

We have therefore proved from induction method that the equation $\large y^3=1+2^{2^x}$ has no solution.
 

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