High School Prove No Solution for Equation $y^3=1+2^{2^x}$ in Natural Numbers

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The equation \( y^3 = 1 + 2^{2^x} \) has been proven to have no solutions in natural numbers. The proof involves analyzing the properties of powers of two and cubic numbers. It demonstrates that the left side, being a perfect cube, cannot equal the right side, which grows exponentially. The discussion highlights the mathematical reasoning and techniques used to arrive at this conclusion. Thus, the equation does not hold for any natural number values of \( y \) and \( x \).
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Prove that the equation $\large y^3=1+2^{2^x}$has no solution in natural numbers.


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Congratulations to the following member for his correct solution:

1. greg1313

Solution from greg1313:

Proof by induction.

Base case: $$1^3-1=0\ne2^{2^x}$$

Inductive step: $$(n+1)^3-1=n(n^2+3n+3)=2^{2^x}$$$n^2+3n+3$ is odd, so it cannot divide $2^{2^x}$.

We have therefore proved from induction method that the equation $\large y^3=1+2^{2^x}$ has no solution.
 

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