Prove that ∫₀^∞ x²e^(-ax²) dx = (1/4)√(π/a³)

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Homework Statement


Given that:

The integral between infinity and -infinity of

e-ax^2 dx = [tex]\sqrt{\pi/a}[/tex]

show that

The integral between 0 and infinity of

x2.e-ax^2 dx = 1/4[tex]\sqrt{\pi/a^3}[/tex]


Homework Equations





The Attempt at a Solution


don't really know where to start
 
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