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Integral (e^-ax)sin(bx) from 0 to infinity

  1. Jan 1, 2014 #1
    1. The problem statement, all variables and given/known data

    integral (e^-ax)sin(bx) from 0 to infinity

    2. Relevant equations



    3. The attempt at a solution

    I want to check if my answer is right

    I got

    \frac { \frac { -1 }{ a } { e }^{ -ax }\quad sinbx\quad -\frac { b }{ { a }^{ 2 } } { e }^{ -ax }\quad cosbx }{ 1+\frac { { b }^{ 2 } }{ { a }^{ 2 } } }

    and when I did the limit to infinity I got zero?

    I'm not sure if it's correct
     
  2. jcsd
  3. Jan 1, 2014 #2

    vela

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    Yup, that's right. The result of the integral is what you get from the lower limit x=0.
     
  4. Jan 1, 2014 #3
    thanks :smile:
     
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