Prove xy+x'z+yz'=xy+x'z using Boolean algebra

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Dear all please help me in solving this question:
I tried my best but I was not able to solve.

Using the basic identities of Boolean algebra show that :
xy+x’z+yz’=xy+x’z


Kindly help me.
 

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syedejaz said:
Dear all please help me in solving this question:
I tried my best but I was not able to solve.

Using the basic identities of Boolean algebra show that :
xy+x’z+yz’=xy+x’z


Kindly help me.

Welcome to the PF.

What are the basic Boolean identity equations? Please list them for us, and tell us which ones you think might apply.
 
berkeman said:
Welcome to the PF.

What are the basic Boolean identity equations? Please list them for us, and tell us which ones you think might apply.

Thank you so much
here is the table from my course book
Untitled-1-2.jpg
 
Last edited:
BTW, are you sure you copied the equation down correctly?

xy+x’z+yz’=xy+x’z


The lefthand side (LHS) and righthand side (RHS) are the same, except for one extra term on the LHS...
 
berkeman said:
BTW, are you sure you copied the equation down correctly?

xy+x’z+yz’=xy+x’z


The lefthand side (LHS) and righthand side (RHS) are the same, except for one extra term on the LHS...

And if you check this with two Karnaugh maps (one for LHS and one for RHS), they differ...
 
berkeman said:
BTW, are you sure you copied the equation down correctly?

xy+x’z+yz’=xy+x’z


The lefthand side (LHS) and righthand side (RHS) are the same, except for one extra term on the LHS...

yes offcourse
 
hello no body knows ): please help me I have to submit my Assigment tomorrow.
 
syedejaz said:
yes offcourse

What do you mean "of course"? The LHS does not equal the RHS, so how can you use any manipulations to show that they are equal?
 
berkeman said:
What do you mean "of course"? The LHS does not equal the RHS, so how can you use any manipulations to show that they are equal?

Dear I am very sorry.
Our university corrected the mistake . They published it on the web.
here is the correct

xy+x’z+yz=xy+x’z

Thanks