Proving a Theorem on Point-Set Topology

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Discussion Overview

The discussion revolves around proving a theorem in point-set topology related to continuous functions on a topological space. The theorem states that a collection of continuous functions separates points from closed sets if and only if the preimages of open sets form a base for the topology on the space.

Discussion Character

  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant requests assistance in proving the theorem regarding continuous functions and their relation to separating points from closed sets.
  • Another participant provides definitions and facts relevant to the theorem, explaining the conditions under which a collection of functions separates points from closed sets and the criteria for a collection of open sets to form a base for the topology.
  • The second participant outlines a proof strategy for the first half of the theorem, involving the use of closures and open sets, while encouraging the original poster to explore the second part independently.
  • A later reply suggests that drawing a diagram may aid in understanding the concepts discussed.

Areas of Agreement / Disagreement

Participants appear to agree on the definitions and the approach to proving the theorem, but the discussion does not resolve the overall proof or the second part of the theorem, leaving it open for further exploration.

Contextual Notes

The discussion includes assumptions about the properties of continuous functions and the topology involved, but does not delve into specific examples or counterexamples that could clarify the theorem further.

ForMyThunder
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I can't seem to find out how to prove this theorem:

A collection {fa | a in A} of continuous functions on a topological space X (to Xa) separates points from closed sets in X if and only if the sets fa-1(V), for a in A and V open in Xa, form a base for the topology on X.

Could anyone help me out? Thanks.
 
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ForMyThunder said:
I can't seem to find out how to prove this theorem:

A collection {fa | a in A} of continuous functions on a topological space X (to Xa) separates points from closed sets in X if and only if the sets fa-1(V), for a in A and V open in Xa, form a base for the topology on X.

Could anyone help me out? Thanks.

hi ForMyThunder,

first let's go over some basic definitions and facts,

1) A collection of continuous functions \{ f_{a} : a \in A \} on a topological space X is said to separate points from closed sets in X iff for every closed set B \subset X, and every x \notin B , \exists a \in A : f_{a}(x) \notin \overline{f_{a}(B)}

2) If for a collection \textbf{B} of open sets of X, for every open set U \subset X and every x \in U there is an element B of \textbf{B} such that x \in B \subset U, then \textbf{B} is a base for the topology of X.

Let \textbf{B} = \{f_{a}^{-1}(V) : a \in A, V \mbox{ open in } X_{a} \}. In light of 2, let U \subset X be open, and let x \in U. since U is open, U' is closed, and x \notin U', so by (1) \exists a \in A : f_{a}(x) \notin \overline{f_{a}(U')}.
Now \overline{f_{a}(U')} is closed, being a closure, therefore \overline{f_{a}(U')}' is open. Since f_{a}(x) \notin \overline{f_{a}(U')}, we have f_{a}(x) \in \overline{f_{a}(U')}', so \exists V \subset \overline{f_{a}(U')}' such that x \in V and V is open.
Since every set is a subset of its closure, now we have: V \subset (f_{a}(U'))', we want to show that f_{a}^{-1}(V) \subset U. This is done by simple facts from set algebra, perhaps you can try to do it on your own?

This shows the first half of the theorem.
 
Last edited:
Awesome, thanks. I think I can figure out the second part. Thanks again.
 
you're welcome. it helps to draw a diagram to get a feel for what's going on :)
 

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