Proving Function Polynomial in Coordinates is Differentiable Everywhere

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Discussion Overview

The discussion centers on proving that a function \( f:\mathbb{R}^n\rightarrow \mathbb{R} \) which is polynomial in the coordinates is differentiable everywhere, specifically focusing on the application of the chain rule in this context.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant presents the function \( f \) as a polynomial expressed in terms of its coordinates and outlines properties of differentiable functions, such as the differentiability of projections, constants, products, and sums of differentiable functions.
  • Another participant questions how the chain rule is applied in the proof of differentiability, seeking clarification on its usage in the context of the polynomial function.
  • A further reply suggests that an example involving a specific projection and a differentiable function could illustrate the application of the chain rule, indicating that \( g \circ \pi_7 \) is differentiable if both components are differentiable.

Areas of Agreement / Disagreement

Participants express uncertainty regarding the application of the chain rule in proving differentiability, with some seeking clarification and others providing examples without reaching a consensus on the method.

Contextual Notes

The discussion does not resolve the specific application of the chain rule, and participants have not agreed on a definitive approach to the proof.

i_a_n
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The question is:
Using the chain rule to prove that a function $f:\mathbb{R}^n\rightarrow \mathbb{R}$ which is polynomial in the coordinates is differentiable everywhere.
(The chain rule is for the use under function composition circumstances, how to apply it here to prove that the function $f$ which is polynomial in the coordinates is differentiable everywhere?)
 
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ianchenmu said:
(The chain rule is for the use under function composition circumstances, how to apply it here to prove that the function $f$ which is polynomial in the coordinates is differentiable everywhere?)

We can write:

$f:\mathbb{R}^n\to \mathbb{R},\quad f(x_1,\ldots,x_n)=\displaystyle\sum_{i_1\geq 0,\ldots,i_n\geq 0}a_{i_1,\ldots,i_n}x_1^{i_1}\ldots x_n^{i_n}$

with finitely many nonnull real coefficientes $a_{i_1,\ldots,i_n}$. Now, use the following properties:$(1)\;$ The projections $\pi_i:\mathbb{R}^n\to\mathbb{R},\quad \pi_i(x_1,\ldots,x_n)=x_i$ are differentable on $\mathbb{R}^n$.

$(2)\;$ Every constant funcion is differentiable on $\mathbb{R}^n$.

$(3)\;$ The product of two differentiable functions on $\mathbb{R}^n$ is differentiable on $\mathbb{R}^n$.

$(4)\;$ The sum of two differentiable functions on $\mathbb{R}^n$ is differentiable on $\mathbb{R}^n$.
 
Fernando Revilla said:
We can write:

$f:\mathbb{R}^n\to \mathbb{R},\quad f(x_1,\ldots,x_n)=\displaystyle\sum_{i_1\geq 0,\ldots,i_n\geq 0}a_{i_1,\ldots,i_n}x_1^{i_1}\ldots x_n^{i_n}$

with finitely many nonnull real coefficientes $a_{i_1,\ldots,i_n}$. Now, use the following properties:$(1)\;$ The projections $\pi_i:\mathbb{R}^n\to\mathbb{R},\quad \pi_i(x_1,\ldots,x_n)=x_i$ are differentable on $\mathbb{R}^n$.

$(2)\;$ Every constant funcion is differentiable on $\mathbb{R}^n$.

$(3)\;$ The product of two differentiable functions on $\mathbb{R}^n$ is differentiable on $\mathbb{R}^n$.

$(4)\;$ The sum of two differentiable functions on $\mathbb{R}^n$ is differentiable on $\mathbb{R}^n$.

But where you used the chain rule? I mean, how to use the chain rule to prove that $f$ is differentiable everywhere?
 
ianchenmu said:
But where you used the chain rule? I mean, how to use the chain rule to prove that $f$ is differentiable everywhere?

Perhaps an example will provide you the adequate outline. Consider $\pi_7(x_1,\ldots,x_n)=x_7$ and $g:\mathbb{R}\to \mathbb{R}$ given by $g(t)=t^3$. As $\pi_7$ and $g$ are differentiable, $(g\circ \pi_7)[(x_1,\ldots,x_n)]=x_7^3$ is also differentiable, etc, etc,...
 

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