Proving Function Polynomial in Coordinates is Differentiable Everywhere

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SUMMARY

The discussion focuses on proving that a function \( f:\mathbb{R}^n\rightarrow \mathbb{R} \) which is polynomial in its coordinates is differentiable everywhere using the chain rule. The function is expressed as \( f(x_1,\ldots,x_n)=\sum_{i_1\geq 0,\ldots,i_n\geq 0}a_{i_1,\ldots,i_n}x_1^{i_1}\ldots x_n^{i_n} \) with real coefficients \( a_{i_1,\ldots,i_n} \). Key properties utilized include the differentiability of projections \( \pi_i \), constant functions, and the sum and product of differentiable functions. An example involving the composition of differentiable functions illustrates the application of the chain rule in this context.

PREREQUISITES
  • Understanding of polynomial functions in multiple variables
  • Knowledge of differentiability in \( \mathbb{R}^n \)
  • Familiarity with the chain rule in calculus
  • Concept of function composition
NEXT STEPS
  • Study the properties of differentiable functions in \( \mathbb{R}^n \)
  • Learn about the chain rule and its applications in multivariable calculus
  • Explore examples of polynomial functions and their differentiability
  • Investigate the implications of differentiability on function composition
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Mathematicians, calculus students, and educators seeking to understand the differentiability of polynomial functions in multiple dimensions and the application of the chain rule.

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The question is:
Using the chain rule to prove that a function $f:\mathbb{R}^n\rightarrow \mathbb{R}$ which is polynomial in the coordinates is differentiable everywhere.
(The chain rule is for the use under function composition circumstances, how to apply it here to prove that the function $f$ which is polynomial in the coordinates is differentiable everywhere?)
 
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ianchenmu said:
(The chain rule is for the use under function composition circumstances, how to apply it here to prove that the function $f$ which is polynomial in the coordinates is differentiable everywhere?)

We can write:

$f:\mathbb{R}^n\to \mathbb{R},\quad f(x_1,\ldots,x_n)=\displaystyle\sum_{i_1\geq 0,\ldots,i_n\geq 0}a_{i_1,\ldots,i_n}x_1^{i_1}\ldots x_n^{i_n}$

with finitely many nonnull real coefficientes $a_{i_1,\ldots,i_n}$. Now, use the following properties:$(1)\;$ The projections $\pi_i:\mathbb{R}^n\to\mathbb{R},\quad \pi_i(x_1,\ldots,x_n)=x_i$ are differentable on $\mathbb{R}^n$.

$(2)\;$ Every constant funcion is differentiable on $\mathbb{R}^n$.

$(3)\;$ The product of two differentiable functions on $\mathbb{R}^n$ is differentiable on $\mathbb{R}^n$.

$(4)\;$ The sum of two differentiable functions on $\mathbb{R}^n$ is differentiable on $\mathbb{R}^n$.
 
Fernando Revilla said:
We can write:

$f:\mathbb{R}^n\to \mathbb{R},\quad f(x_1,\ldots,x_n)=\displaystyle\sum_{i_1\geq 0,\ldots,i_n\geq 0}a_{i_1,\ldots,i_n}x_1^{i_1}\ldots x_n^{i_n}$

with finitely many nonnull real coefficientes $a_{i_1,\ldots,i_n}$. Now, use the following properties:$(1)\;$ The projections $\pi_i:\mathbb{R}^n\to\mathbb{R},\quad \pi_i(x_1,\ldots,x_n)=x_i$ are differentable on $\mathbb{R}^n$.

$(2)\;$ Every constant funcion is differentiable on $\mathbb{R}^n$.

$(3)\;$ The product of two differentiable functions on $\mathbb{R}^n$ is differentiable on $\mathbb{R}^n$.

$(4)\;$ The sum of two differentiable functions on $\mathbb{R}^n$ is differentiable on $\mathbb{R}^n$.

But where you used the chain rule? I mean, how to use the chain rule to prove that $f$ is differentiable everywhere?
 
ianchenmu said:
But where you used the chain rule? I mean, how to use the chain rule to prove that $f$ is differentiable everywhere?

Perhaps an example will provide you the adequate outline. Consider $\pi_7(x_1,\ldots,x_n)=x_7$ and $g:\mathbb{R}\to \mathbb{R}$ given by $g(t)=t^3$. As $\pi_7$ and $g$ are differentiable, $(g\circ \pi_7)[(x_1,\ldots,x_n)]=x_7^3$ is also differentiable, etc, etc,...
 

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