Proving homogeneity of dy/dx=(x+3y)/(x-y)

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karush
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$\dfrac{dy}{dx}=\dfrac{x+3y}{x-y}$
ok well following the book example: divide numerator and denominator by x

$\dfrac{dy}{dx}=\dfrac{1+3\dfrac{y}{x}}{1-\dfrac{y}{x}}$

apparently, thus this is homogeneous but not sure why?

next solve the DE:unsure:
 
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