Proving Inclusion of Vector Subspaces in W: A Scientific Approach

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Discussion Overview

The discussion revolves around the question of proving that if U and V are vector subspaces of W and their union is also a subspace of W, then either U or V must be contained within the other. The scope includes theoretical reasoning and mathematical proof strategies.

Discussion Character

  • Exploratory
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant asks how to prove that either U or V is contained in the other given that their union is a subspace of W.
  • Another participant suggests using intuition and examples, such as a line and a plane in R^3, to guide the proof process.
  • A third participant proposes a proof strategy involving the construction of a basis for the union of U and V, arguing that if U and V are not contained in each other, a contradiction arises when considering linear combinations of basis vectors.
  • One participant acknowledges the utility of examples but emphasizes that examples alone do not constitute a proof.
  • A later reply questions the nature of the original inquiry, suggesting it resembles a homework problem and indicating that the forum may not be the appropriate venue for such questions.

Areas of Agreement / Disagreement

Participants express differing views on the adequacy of examples versus formal proofs, and there is no consensus on a definitive proof approach. The discussion remains unresolved regarding the proof's formulation.

Contextual Notes

Limitations include the potential dependence on specific definitions of vector subspaces and the need for clarity on the dimensionality of the intersection of U and V.

Oster
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If U and V are vector subspaces of W and if U union V is also a subspace of W, how would i show that either U or V is contained in the other?
 
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Do you have an intuition for how it works?
(If you don't, think of say a line and plane in R^3. When is their union also a vector space?)
Then try translating that image into a proof.
 
If U and V were not contained in each other, you could find a basis of their union of the form

u_1,\dots,u_a,v_1,\dots,v_b,w_1,\dots,w_c

where the u's belong to U, the v's belong to V and the w's belong to the intersection (if this is not a zero dimensional space). Consider for example the vector

u_1+v_1

This vector can't belong to the union of U and V, because the basis above is composed of linearly independent vectors. So the union of U and V is not a vector space, a contraddiction.
 
@ Simon Tyler. yeah I've thought about those examples, like when the line is on the plane or one of the subspaces is the zero vector. But giving examples doesn't prove it..
Thanks a lot Petr. More questions to come soon =D
 
@ Oster: I was hoping that thinking about that example would lead you to a proof like Petr's. Basically, you're question sounds like a homework problem -- which isn't helped by your small number of posts to these forums. These forums are not a place for homework help. I apologize if I've got you wrong and it as a genuine question.
 

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