Proving Reflexive, Symmetric and Transitive Properties of Relation R on P(U)

Click For Summary
SUMMARY

The relation R on P(U), defined by A R B if A ∩ C = B ∩ C, is proven to be symmetric and transitive. Symmetry is established as A ∩ C = B ∩ C implies B ∩ C = A ∩ C. Transitivity is confirmed by demonstrating that if A ∩ C = B ∩ C and B ∩ C = D ∩ C, then A ∩ C = D ∩ C. However, the reflexive property is not adequately addressed, as the definitions require clarification regarding the specific elements involved in the relation.

PREREQUISITES
  • Understanding of set theory and universal sets
  • Familiarity with the concepts of reflexive, symmetric, and transitive relations
  • Knowledge of intersection operations in set theory
  • Ability to formulate and interpret mathematical proofs
NEXT STEPS
  • Study the definitions and examples of reflexive, symmetric, and transitive relations in set theory
  • Explore the properties of set intersections and their implications in relations
  • Learn how to construct formal proofs for mathematical relations
  • Investigate additional examples of relations on power sets and their properties
USEFUL FOR

Mathematicians, computer scientists, and students studying discrete mathematics or set theory who are interested in understanding the properties of relations on sets.

leigh ramona
Messages
2
Reaction score
0
Let U be a universal set, and let C be any subset of U. Let R be the relation on P(U) defined by A R B if $A \cap C = B \cap C$. Determine whether the relation is reflexive, symmetric, and/or transitive. Prove you answer.
 
Last edited by a moderator:
Physics news on Phys.org
First, do you know what "reflexive", "symmetric", and "transitive" mean? Write down the definitions and show that this relation satisfies those definitions.
 
So reflexive is equal to each other. Like x R x.
Symmetric is x R y = y R x
Transitive is if x R y and y R z, then x R z.

The relation is symmetric because if A \cap C = B \cap C, then C \cap A = C \cap B. Is this correct?

The relation is also transitive, because if A \cap C and B \cap C, then A \cap B.

I'm not sure about the reflexive.
 
leigh ramona said:
So reflexive is equal to each other. Like x R x.
Your sentence does not make sense because it lacks the subject: what is equal to each other?. And when you say $xRx$, I'll ask you: what is $x$? Do you mean $xRx$ holds for some unspecified $x$, for all $x$, for some specific $x$? What set does $x$ range over?

leigh ramona said:
Symmetric is x R y = y R x
This sentence is also problematic. For each $x$ and $y$, $xRy$ is either true or false. What do you mean by $xRx=yRx$? For which $x$ and $y$?

leigh ramona said:
Transitive is if x R y and y R z, then x R z.
This would be correct if you added "for all $x$, $y$ and $z$".

leigh ramona said:
The relation is symmetric because if A \cap C = B \cap C, then C \cap A = C \cap B. Is this correct?
What you wrote is true, but what does this have to do with $R$? Please enclose formulas in dollar signs: \$A\cap C\$.

leigh ramona said:
The relation is also transitive, because if A \cap C and B \cap C, then A \cap B.
This does not makes sense because $A\cap C$ cannot be true or false: it's a set. Therefore, you can't write "If $A\cap C$...".

If you increase the level of your precision, it will help you not only to communicate more clearly, but to understand the problem and definitions better as well.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
6
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K