Proving the 2:1 Ratio of a Triangle's Medians at the Centroid Using Vectors

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SUMMARY

The discussion focuses on proving the 2:1 ratio of a triangle's medians at the centroid using vector analysis. The triangle ABC has midpoints D, E, and F on sides BC, AC, and AB, respectively, with G as the centroid where the medians intersect. The key vector equation GA + GB + GC = 0 confirms that the centroid divides each median in a 2:1 ratio, with the segments from the centroid to the vertices being proportional. The proof relies on understanding the relationships between the vectors and their coefficients.

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pjallen58
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I am trying to figure out how to prove the 2:1 ratio of a triangle's medians at the centroid using vectors. Example if I had a triangle ABC with midpoints D of BC, E of AC and F of AB. I know G is where the medians intersect. I have seen many proofs and understand the process that proves the addition of the vectors from the centroid to the vertices are zero i.e. GA+GB+GC=0.
vectorsum_dreieck.GIF

Does this prove the 2:1 ratio? I cannot find anything explaining how to prove the actual 2:1 ratio. I am not sure if I am missing something or what. Any help or suggestions would be appreciated. Thanks.
 
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pjallen58 said:
I am trying to figure out how to prove the 2:1 ratio of a triangle's medians at the centroid using vectors. Example if I had a triangle ABC with midpoints D of BC, E of AC and F of AB. I know G is where the medians intersect. I have seen many proofs and understand the process that proves the addition of the vectors from the centroid to the vertices are zero i.e. GA+GB+GC=0.
View attachment 14402
Does this prove the 2:1 ratio? I cannot find anything explaining how to prove the actual 2:1 ratio. I am not sure if I am missing something or what. Any help or suggestions would be appreciated. Thanks.

Hi pjallen58! :smile:

Yes, because, for example, a + 2(d) is 1/3 of the way,

and that's a + 2(1/2(b + c)), = a + b + c! :smile:
 

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