Proving the Evenness of n^3: Simple Verification for Homework

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Homework Help Overview

The problem involves proving that if \( n^3 \) is even, then \( n \) must also be even, where \( n \) is an integer. The discussion centers around understanding the implications of evenness in integers and the relationships between \( n \) and \( n^3 \).

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the original poster's attempt to prove the converse of the statement, noting that the proof provided only establishes that if \( n \) is even, then \( n^3 \) is even. Some suggest examining the factors of \( n^3 \) to understand the implications of evenness. Others mention the usefulness of considering the contrapositive of the statement.

Discussion Status

The discussion is ongoing, with participants clarifying the distinction between the original statement and its converse. Some guidance has been offered regarding the importance of understanding the contrapositive in proofs, and there is acknowledgment of the need for careful reasoning in mathematical proofs.

Contextual Notes

There is a focus on ensuring clarity in the definitions and implications of even and odd integers, as well as the terminology related to implications, converses, and contrapositives. Participants are encouraged to explore these concepts without jumping to conclusions.

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Homework Statement



Let n be an integer. Prove that if n^3 is even, then n is even.

Homework Equations





The Attempt at a Solution



Suppose n is even. That is n=2m, for some mεZ.
Then, n^3=(2m)^3=8m^3=2(4m^3).
Since 4m^3 is an integer, n^3 will be even.

Now, i proved that if n is even, then n^3 is even. So would this be a valid proof in this context?
 
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NATURE.M said:

Homework Statement



Let n be an integer. Prove that if n^3 is even, then n is even.

Homework Equations





The Attempt at a Solution



Suppose n is even. That is n=2m, for some mεZ.
Then, n^3=(2m)^3=8m^3=2(4m^3).
Since 4m^3 is an integer, n^3 will be even.

Now, i proved that if n is even, then n^3 is even. So would this be a valid proof in this context?

Looks fine.

Edit: I misread the problem statement as "if n is even then n3 is even." My mistake.
 
Last edited:
Your proof is showing that if n is even then n^3 is even.

You want to show the converse that if n^3 is even then n is even.

It is semantics and may seem silly in this sort of proof but in more difficult proofs you have to be careful of what you are saying.

Edit: Take the factors of n^3 and see what that means to be even.


Assume n^3 is even and n is an integer. Well, n^3 = n* n* n. Since n^3 is even n*n*n is even which means that either n or n or n is divisible by two. Therefore, n is an integer divisible by two; n is even.
 
Last edited:
Jufro said:
Your proof is showing that if n is even then n^3 is even.

You want to show the converse that if n^3 is even then n is even.

It is semantics and may seem silly in this sort of proof but in more difficult proofs you have to be careful of what you are saying.

Assume n^3 is even and n is an integer. Well, n^3 = n* n* n. Since n^3 is even n*n*n is even which means that either n or n or n is divisible by two. Therefore, n is an integer divisible by two; n is even.

It's good to point out what he did wrong, but I presume you know you are not supposed to supply complete solutions.
 
I just wanted to make sure that I wasn't missing something.

To comply better with PF rules I updated my post
 
So many of these problems are made easier when you look at the contrapositive of the claim. Here it is just that if n is odd, then n^3 is odd.
 
Jufro said:
Your proof is showing that if n is even then n^3 is even.

You want to show the converse that if n^3 is even then n is even.

It is semantics and may seem silly in this sort of proof but in more difficult proofs you have to be careful of what you are saying.

Edit: Take the factors of n^3 and see what that means to be even.


Assume n^3 is even and n is an integer. Well, n^3 = n* n* n. Since n^3 is even n*n*n is even which means that either n or n or n is divisible by two. Therefore, n is an integer divisible by two; n is even.
Yeah, that's what I was really unsure about, but thanks for clarifying.
 
verty said:
So many of these problems are made easier when you look at the contrapositive of the claim. Here it is just that if n is odd, then n^3 is odd.

The solution to the actual problem uses the contrapositive method you described, where n is odd, then n^3 is odd. Though, I haven't studied contrapositive proofs yet, so I posted an alternative method above.
 
What you proved was the converse, not the contrapositive.

If you're uncertain about these terms, maybe this will help.

Implication P => Q (if P then Q)
Converse: Q => P
Contrapositive: ~Q => ~P (if not Q, then not P)

There's another term for the converse of the contrapositive, but I forget what it is.

An implication and its contrapositive are always equivalent (i.e., they have exactly the same truth table values), but an implication and its converse are not equivalent.

Here are some examples.
Implication: If x = 2, then x2 = 4

Converse of the implication: If x2 = 4, then x = 2 (not necessarily true, as x could be -2)

Contrapositive of the implication: If x2 ≠ 4, then x ≠ 2
 
  • #10
Mark44 said:
What you proved was the converse, not the contrapositive.

If you're uncertain about these terms, maybe this will help.

Implication P => Q (if P then Q)
Converse: Q => P
Contrapositive: ~Q => ~P (if not Q, then not P)

There's another term for the converse of the contrapositive, but I forget what it is.

An implication and its contrapositive are always equivalent (i.e., they have exactly the same truth table values), but an implication and its converse are not equivalent.

Here are some examples.
Implication: If x = 2, then x2 = 4


Converse of the implication: If x2 = 4, then x = 2 (not necessarily true, as x could be -2)

Contrapositive of the implication: If x2 ≠ 4, then x ≠ 2

Thanks a lot Mark44. It makes sense to me now why the solutions manual proved the statement, "if n^3 is even, then n is even" by giving a proof of " if n is odd, then n^3 is odd", which is the contrapositive statement. This would be valid as the implication statement is equivalent to its contrapositive statement, as you pointed out.
 

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