Proving the Limit of 2^(1/n) = 1

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SUMMARY

The limit of the sequence defined by 2^(1/n) converges to 1 as n approaches infinity. The discussion emphasizes the importance of demonstrating that the sequence is decreasing and remains greater than 1 for all natural numbers n. To prove this limit, participants suggest taking the natural logarithm of the expression 2^(1/n) - 1 < epsilon and solving for n, which provides a clear pathway to establish the limit rigorously.

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Homework Statement



How do I prove that lim 2^(1/n) = 1?

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The Attempt at a Solution

 
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What have you done so far?
 
This is actually part of a series problem, so I have determined that the sequence of a_n's is decreasing and that it seems to converge to 1. I know that I need to find N \in the naturals such that |2^(1/n)| < epsilon, but I can't seem to figure out how to solve in terms of epsilon.
 
Since 2^{1/n} is always greater than 1 (prove this!), you can forget the absolute value. Try taking the natural log of both sides of 2^{1/n}-1&lt;\epsilon and solving for n.
 

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