Proving the Relationship Between Pi and 1/9

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prove that

[tex]\frac{1}{1^2.3^3.5^2}-\frac{1}{3^2.5^3.7^2}+\frac{1}{5^2.7^3.9^2}-...=\frac{1}{9}-\frac{\pi}{2^6}-\frac{\pi^3}{2^9}[/tex]
 
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