Proving triangle ACB is congruent to triangle ADB

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hecate
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can anyone explain how to do this proof?
Given: angle ABC is congruent to angle ABD, angle ACB is congruent to angle ADB
Prove: triangle ACB is congruent to triangle ADB.
thank you!
 

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Do you have any theorems that you can use? Like the angle-side-angle theorem?

If you have that, and you can show that BAD and BAC are the same, then you're done.
 
yeah...i think i could use the ASA theorem...but i don't know how to explain it and when to use it.
 
You know that the sum of the interior angles of a triangle is always the same, right?
 
So you know that:
ABC + BCA + CAB = ABD + BDA + DAC

from the problem you have:
ABC=ABD
and
BCA=BDA

so if you make the substitutions you get
ABC+BCA+CAB=ABC+BCA+DAC

ABD+BCA can be cancellet from both sides, so you get
CAB=DAC
 
oh...i get it now! thanx!