Proving using rodrigue's formula (a very challenging question)

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Discussion Overview

The discussion revolves around proving a specific equation involving Rodrigues' formula for orthogonal polynomials, particularly focusing on the expression (n+1)Pn+1(x)-(2n+1)xPn(x)+nPn-1(x)=0. The scope includes mathematical reasoning and problem-solving techniques related to differentiation and polynomial properties.

Discussion Character

  • Mathematical reasoning, Homework-related, Exploratory

Main Points Raised

  • One participant seeks assistance in proving the equation using Rodrigues' formula.
  • Another participant inquires about the methods attempted so far to solve the problem.
  • A participant expresses difficulty with differentiation, indicating it hampers their progress.
  • There is a challenge posed regarding the lack of details about the attempts made to solve the problem.
  • A participant reports progress by finding a formula to differentiate multiple times and is now working on identifying Pn+1 and Pn-1 using Rodrigues' formula.

Areas of Agreement / Disagreement

The discussion remains unresolved, with participants expressing varying levels of progress and understanding, and no consensus on the approach to the proof has been reached.

artisticmath
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This is a very challenging question I would like your help guys to solve this question.
Prove (n+1)Pn+1(x)-(2n+1)xPn(x)+nPn-1(x)=0 using Rodriguez's formula
 
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What have you tried so far?
 
The problem is in differentiating ..I really find it very difficult to differentiate..
 
You still haven't said what you tried. Or are you saying that, because you are "find it very difficult to differentiate", you simply haven't tried at all?
 
I am making a progress .. I found a formula that allowed me to differentiate (n+1) times, so now am working on finding Pn+1 and Pn-1 by the Rodriguez formula , and then substituting them back in the equation..
 

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