Question about a car turning on ice.

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    Car Ice Turning
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SUMMARY

When a car is turning in a circular motion and encounters a patch of ice, the lack of friction (μ=0) eliminates the centripetal force required to maintain the turn. Consequently, the car will not continue along the circular path but will instead move in a straight line due to inertia. This phenomenon is explained by the equation μmg=mv²/r, where the absence of friction means no force is available to sustain the circular motion.

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preluderacer
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If I was turning in a circular motion in a car, then I hit a patch of ice making the road frictionless. Would my car just go straight? I always have a hard time on these intuitive questions.
 
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Right well if the friction is providing the centripetal force then μmg=mv2/r. Hence if μ=0, then no force is providing the necessary force to carry it in that circular motion, hence yes it would go straight.
 

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