tunafish
- 10
- 0
Hi fellas! Would you help me solve this problem I have?
Let's take a function [itex]f:\mathbb{R}^n\rightarrow \mathbb{R}[/itex].
And so [itex]f(x_1,x_2,...,x_n)=y; \;\;y\in \mathbb{R}[/itex]
It's of course a function of many variables, but can this be considered a function of a vector whose components are the [itex]x_n[/itex]'s?
And if it actually is a function of a vector, in which way are the basis involved?
For example if we take function [itex]f(x,y)=x+y[/itex] is it intended that we are working with
[itex]f(x,y)=x\vec{e}_x+y\vec{e}_y[/itex] ?
If so why then the result [itex]f(x,y)[/itex] is a scalar? And how could i put togheter the coefficient of different vectors??
But most of all..where are the basis vectors gone? Thanks for your help!
(ps: if this is NOT a function of vectors could you make me an example of one which is??)
Let's take a function [itex]f:\mathbb{R}^n\rightarrow \mathbb{R}[/itex].
And so [itex]f(x_1,x_2,...,x_n)=y; \;\;y\in \mathbb{R}[/itex]
It's of course a function of many variables, but can this be considered a function of a vector whose components are the [itex]x_n[/itex]'s?
And if it actually is a function of a vector, in which way are the basis involved?
For example if we take function [itex]f(x,y)=x+y[/itex] is it intended that we are working with
[itex]f(x,y)=x\vec{e}_x+y\vec{e}_y[/itex] ?
If so why then the result [itex]f(x,y)[/itex] is a scalar? And how could i put togheter the coefficient of different vectors??
But most of all..where are the basis vectors gone? Thanks for your help!
(ps: if this is NOT a function of vectors could you make me an example of one which is??)