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Question about generator of cyclic group

  1. Oct 15, 2012 #1
    Say we have a cyclic group G, and a generator a in G. This means [a] = G. We know the order of an element a, is the order of the group it generates, [a], and also this is the smallest integer s such that as=e, where e is the identity element. In this case, [a]=G, so s is just the order of G.


    Now my question is, since a is a generator of G, this means there is an integer t such that for every m in G, at=m. But is it always true that t ≤ s? What I mean is, does the integer s such that as = e (the identity) always have to be greater than the integer t such that at=m (where m is just any old element in G, NOT the identity!) Could you have a situation say where you have a group G and generator a, and say e is the identity element in G, and m is some other element in G, and a5=e, but a10=m?


    Thanks
     
  2. jcsd
  3. Oct 15, 2012 #2
    What happens with as+1? Well, you get asa = ea = a, so you start the same cycle over again.
     
  4. Oct 15, 2012 #3
    Number Nine, thank you very much for this, that makes complete sense and clears my confusion and I don't know why I didn't think of it this way before!
     
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