Question about nondisjunction - help please!!! My question is related specifically to Trisomy 21. Lets consider spermatogenisis. I know that nondisjunction can occur in either anaphase 1 or anaphase 2, but I was wondering what the outcome of the number of chromosomes is in each of the 4 resulting sperm cells? From what I can see, if the nondisjunction event occurs during anaphase 1, there will be 2 resulting cells with n+1 chromosomes (24) and 2 cells with n-1 (22) chromosomes (where n = the normal haploid number). However, when the nondisjunction events occurs during anaphase 2 I see one n+1 cell resulting, one n-1 cell, and two normal cells with n chromosomes. Please tell me if this analysis is correct. If not, please give me the correct answer. Thank you for your help!!