Question about particle reaction

  • Thread starter Clear Mind
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  • #1
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It's an easy question, let's consider this reaction:
##N+\nu_e \rightarrow e^{-}+P##
Is this reaction possible? If is not, what does violate?

(I think is possible because charge is conserved, baryon, lepton and fermion numbers are conserved. But i'm not totally sure)
 

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  • #2
dukwon
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Yes, this is charged-current neutrino scattering. It's one of the processes that neutrino detectors look for.
 
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  • #3
Orodruin
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Yes.

However, note that for free neutrons, it is much more likely that the neutrons will decay naturally unless you have an outrageously high neutrino flux.
 
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Thank you all!
It's one of the processes that neutrino detectors look for.
I suppose that the cross section it's really small ...
 
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Orodruin
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Thank you all!

I suppose that the cross section it's really small ...

This is why neutrino detectors are really big ... :)
 
  • #6
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From a few day i've started to study particle physics, so i'm still a little bit confused ... I was wondering:
##N+\nu_e \rightarrow e^{-}+P##
it's a weak interaction, so it should violate c-symmetry, thus:
##\bar{N}+\bar{\nu_e} \rightarrow e^{+}+\bar{P}##
shouldn't be possible ...
I'm a little puzzled :(
 
  • #7
dukwon
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It is possible if you make both a charge inversion and a parity operation, since the weak force couples to left-handed fermions and right-handed antifermions.

Usually when we talk about an antiparticle it's the CP-conjugate rather than the C-conjugate.
 
  • #8
ChrisVer
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yes it is impossible, because you turned a right-handed neutrino into a right-handed antineutrino .... which doesn't exist [in SM]
 
  • #9
dukwon
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yes it is impossible, because you turned a right-handed neutrino into a right-handed antineutrino .... which doesn't exist [in SM]

It's the other way round. Antineutrinos have to be right-handed in the Standard Model.
 
  • #10
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yes it is impossible, because you turned a right-handed neutrino into a right-handed antineutrino .... which doesn't exist [in SM]
Right! i was considering only charge, baryon, lepton and fermion numbers but not the parity :s
 
  • #11
ChrisVer
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It's the other way round. Antineutrinos have to be right-handed in the Standard Model.

OMG! indeed! Well I'm always forgetting the a-priori left and right... [except for when I write the doublets]...
 
  • #12
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C and CP violation do not mean the process is completely impossible. It can have a different dependence on the relative angles (P violation), or occur a bit more or less frequent even with an additional P transformation (CP violation), but it is still possible.
 

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