Question about something reaching exactly +

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Homework Help Overview

The discussion revolves around understanding the concept of +2g acceleration in the context of a turn, specifically focusing on the implications of this acceleration type during circular motion.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to clarify the meaning of +2g acceleration when turning, seeking a better understanding than what was provided by peers and teachers. Participants discuss the nature of acceleration, distinguishing between tangential and normal (centripetal) acceleration, and explore the mathematical relationship involving velocity and radius.

Discussion Status

Participants are actively engaging with the problem, with some providing mathematical insights and clarifications. There is a productive exchange regarding the interpretation of acceleration and its application in the context of circular motion, though no consensus has been reached on the original poster's understanding.

Contextual Notes

The discussion includes a focus on the definitions and implications of acceleration types, with an emphasis on the mathematical formulation related to circular motion. The original poster's initial confusion highlights the need for clearer explanations of the concepts involved.

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[SOLVED] Question about something reaching exactly +

Homework Statement


Sorry, I accidentally hit the enter button. Anyways my question is about something reaching exactly +2G acceleration on a turn. I tried asking my friends and teacher about it but it didn't exactly make sense the way they explained it. I just want to know what that means to have a +2g acceleration when turning
 
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Tangential or normal? I think you'll have to explain more about what your friends and teachers explained and express that in the form of a question.
 
Last edited:
I think normal.
 
Normal (centripetal) acceleration is given by v^2/r, where r is the radius of the turn and v is the velocity. If that's equal to 2g, then 2g=v^2/r.
 
Oh okay. That makes sense now. So that would mean that 2(-9.81m/s^2) = v^2/r right?
 
Right. Except I wouldn't put a minus sign on g in this context. g is just a magnitude, not a direction.
 
Oh okay. Thanks so much!
 

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