Question on a Double Split Problem

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SUMMARY

The discussion focuses on calculating the distance between the third-order red fringe and the third-order yellow-green fringe in a double-slit experiment. The slits are 0.153 mm apart, with red light at a wavelength of 665 nm and yellow-green light at 565 nm, projected onto a screen 2.17 m away. The calculations reveal that the distance between the fringes is 0.00043 m, which was initially miscalculated as 0.0043 m due to a decimal placement error. The correct approach involves using the formula Sin(theta) = m(wavelength/d) to derive the fringe positions accurately.

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1. Two slits are 0.153 mm apart. A mixture of red light (wavelength = 665 nm) and yellow-green light (wavelength = 565 nm) falls on the slits. A flat observation screen is located 2.17 m away. What is the distance on the screen between the third-order red fringe and the third-order yellow-green fringe?

d= 0.153mm = 1.53 x 10^-3m
red wavelength= 665 nm = 6.65 x 10 ^-7 m
Yellow-green wavelength = 565 nm = 5.65 x 10^-7 m
x = 2.17m
m = 3




2. Sin theta = m (wavelength/d)



3. red:
Sin Theta = 3(6.65 x 10^-7) / (1.53 x 10^-3) = 0.0013m
Tan Theta = 0.0013 = y/x = y/2.17
red y= 0.00283

yellow-green:
Sin theta = 3 (5.65 x 10^-7) / (1.53 x 10^-3) = 0.0011
Tan theta = 0.0011 = y/x = y/2.17
yellow-green y= 0.0024


red y - yellowgreen y = .00283 - .0024 = 0.00043



This is not right for some reason.
What am I doing wrong?
 
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ok the answer was .0043, but I don't see where the decimal is wrong...
 
ok got it, nevermind.
 

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