Question on Triangles and the lines intersecting through it

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SUMMARY

The discussion focuses on solving a geometry problem involving triangle ABC, where points L and M divide sides AB and BC in the ratio of 2:3, respectively. The intersection of lines AM and LC at point P leads to the need to find the ratio of segments AD to DC, created by a line drawn parallel to BA from point P. Participants emphasize the importance of accurately sketching the triangle to visualize the problem and clarify the ratios involved.

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Homework Statement



In triangle ABC, point L and M divides the sides AB and BC in the ratio 2:3 respectively. AM and LC intersect at point P. From point P a line parallel to BA is drawn intersecting at D. Find the ratio of AD:DC

The Attempt at a Solution



I have attached the picture of the triangle which is all I could make from the question. Please help me out
 

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  • TRIANGLE 1.JPG
    TRIANGLE 1.JPG
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Please show your best attempt at the problem.
This helps us to best help you.

In triangle ABC, point L and M divides the sides AB and BC in the ratio 2:3 respectively.
"respectively" does not mean anything here.

Do you mean that |BL|/2=|LA|/3 and |BM|/2 = |MC|/3 or what?
Is ABC a scalene triangle?

Note: you can probably make headway just by carefully constructing a triangle and measuring.
You certainly want a sketch that better represents the situation.
 

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