Question related to conductivity in a beaker

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Discussion Overview

The discussion revolves around a chemistry problem involving the conductivity of a solution during a titration of sulfuric acid into barium hydroxide. Participants explore the behavior of conductivity in relation to the chemical reactions occurring in the solution, particularly focusing on the transition points during the titration process.

Discussion Character

  • Homework-related, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant presents a multiple-choice question regarding the conductivity of the solution at various stages of the titration process.
  • Another participant suggests that the conductivity is related to the presence of dissociated species in the solution, specifically mentioning barium hydroxide and barium sulfate.
  • A different participant asserts that the answer is option e, explaining that the initial addition of acid neutralizes the solution, leading to a temporary loss of conductivity, which is then restored with further acid addition.
  • One participant questions the neutrality of the solution when equal amounts of acid and base are present, indicating a need for clarification on this point.
  • Another participant notes that barium sulfate precipitates, resulting in an equal amount of H+ and OH-, which forms water.

Areas of Agreement / Disagreement

Participants express differing views on the behavior of conductivity during the titration, particularly regarding the effects of neutralization and precipitation. The discussion remains unresolved with multiple competing interpretations of the conductivity changes.

Contextual Notes

There are unresolved assumptions regarding the definitions of neutrality and the specific conditions under which conductivity changes occur during the titration process.

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Homework Statement



A chemist filled a burette with a solution of sulfuric acid. She then titrated it into a solution of barium hydroxide to a point where there was excess acid. If a conductivity set-up is placed in the beaker with the barium hodroxide at the start of the reaction, what will happen?


Homework Equations



None


The Attempt at a Solution



This is a multiple choice question


a. Bulb glows continually
b. Bulb never glows
c. Bulb will nto glow until the acid is titrated
c. Bulb will glow then stop
e. The blub will glow, stop, then glow again.

The answer is e but I am unsure why it has the glow, stop, and then glow again effect.
 
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You are looking for dissociated species in solution. At first you have barium hydroxide then you have barium sulfate at equivalence. What happens when you add the next drop of ACID?
 
Oh, this question is old, but I was able to get the answer. It's E because with more acid, that neutralizes the solution which means no conductivity. Then with more acid, it's unbalanced, and will conduct again.

Hm ... looking back at this, can you explain why the solution is neutral if there is even amounts of acid and base substances?
 
Barium sulfate precipitates leaving an equal amount of H+ and OH-... water.
 

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