Questions about the Photoelectric Effect

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Discussion Overview

The discussion revolves around the photoelectric effect, specifically addressing the relationship between photon frequency, intensity, and electron ionization. Participants explore concepts related to wave-particle duality, the nature of photons, and how amplitude and intensity relate to the energy of light waves.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants question why electron ionization is dependent on frequency rather than intensity, suggesting that intensity might imply a higher energy wave due to increased amplitude.
  • Others clarify that increasing intensity corresponds to an increase in the number of photons, with each photon retaining the same energy regardless of intensity.
  • There is a discussion about whether a larger amplitude wave could be considered a single high-energy wave or many photons, with some suggesting that the wave's construction does not change the individual energy of the photons.
  • One participant proposes that if two photons were absorbed by the same electron, it might lead to ionization, even if the frequency is not sufficient, likening it to being struck by lightning twice.
  • Another participant confirms that the amplitude squared relates to the density of photons, reinforcing the idea that increased amplitude results in more photons rather than higher energy per photon.

Areas of Agreement / Disagreement

Participants express varying views on the implications of intensity and amplitude in relation to photon energy and the photoelectric effect. No consensus is reached regarding the interpretation of wave properties and their impact on photon behavior.

Contextual Notes

Limitations include the reliance on definitions of intensity and amplitude, as well as the unresolved nature of how wave properties interact with particle behavior in the context of the photoelectric effect.

Kidphysics
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Thought to put this here because of the wave-particle duality ties. My question, that I already asked a tutor was how come electron ionization is due to frequency, and not intensity.

He told me that it was because of nature's "no free lunch" policy and that changing the intensity was just adding two distinct waves constructively. My question was that since the two different waves are going to occupy the same space wouldn't the photon, or the single photon wave's total energy increase as a whole? Why doesn't the change in INTENSITY not enough for the photoelectric effect? Thank you.
 
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Increasing the intensity just means increasing the number of photons. Each will still have the same energy.
 
matonski said:
Increasing the intensity just means increasing the number of photons. Each will still have the same energy.

thank you for your answer, but what about increasing the wave's amplitude? Doesn't a bigger amplitude= more energetic wave? Or does high amplitude also just mean more photons (in one area) and this was what my tutor was trying to say. If it is I have one remaining question. Thanks in advance for the help.
 
Last edited:
Bigger amplitude just means more photons also, since intensity is the square of the amplitude. More photons means a more energetic wave. But again, each photon still has the same energy.
 
matonski said:
Bigger amplitude just means more photons also, since intensity is the square of the amplitude. More photons means a more energetic wave. But again, each photon still has the same energy.

If two photon waves were to "construct" why can we not think of this new wave as a single photon wave? Why do we say that this single wave with a large amplitude is "many photons? If we were to draw it, would it not be conglomerated into one single wave?

Construction is a wave property, so, I'm guessing that photons CAN construct into a single entity- a single high energy wave, but since in this experiment the individual photons are retaining their individual energies they aren't "meshing" and they are behaving like particles. Is this correct?
 
Kidphysics said:
If two photon waves were to "construct" why can we not think of this new wave as a single photon wave? Why do we say that this single wave with a large amplitude is "many photons? If we were to draw it, would it not be conglomerated into one single wave?

Construction is a wave property, so, I'm guessing that photons CAN construct into a single entity- a single high energy wave, but since in this experiment the individual photons are retaining their individual energies they aren't "meshing" and they are behaving like particles. Is this correct?

The wave will be absorbed only one quanta of energy (or photon) at a time so having a bigger wave won't make a difference. Maybe what your getting at is that if two photons were absorbed by the same electron then it could be ionized even though the frequency is incorrect. This may be possible but it would be like getting hit by lighting twice.
 
Joseph14 said:
Maybe what your getting at is that if two photons were absorbed by the same electron then it could be ionized even though the frequency is incorrect.

Okay this answer (with the others) helps me to conclude my confusion.

Obviously the photoelectric effect is dealing with quanta of energy or photons in their particular form.

I thought that possibly the electron could be hit by both photons- if they were to mesh into a constructive wave- where they could 'strike' the electron at the same time. I know this meshing is a wave property, and I've learned that when we are talking about a photon wave with a high amplitude, or a photon wave with high intensity, that we are actually talking about a conglomerate wave of individual photons. Yes?
 
Yes. Roughly, the amplitude squared is equal to the density of photons. Two waves can interfere and create a larger amplitude, but that just means more photons.
 

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