Quick question about Electrochemistry anode and cathode

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SUMMARY

The discussion centers on identifying the anode and cathode in electrochemical cells involving the half-reactions of Pb/Pb2+ and Ag/Ag+, as well as Ni/Ni2+ and Zn/Zn2+. Pb is confirmed as the anode and Ag as the cathode in the first case, with electrons flowing toward Ag. In the second case, Zn serves as the anode and Ni as the cathode, with electrons flowing toward Ni. The key principle emphasized is that reduction occurs at the cathode and oxidation at the anode, determined by the standard reduction potentials.

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qpham26
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Homework Statement


Pb/Pb2+ and Ag/Ag+

Ni/Ni2+ and Zn/Zn2+
Which one is the anode and cathode?
Toward which metal do the electrons flow?



The Attempt at a Solution



2Ag2+ + Pb ⇔ 2Ag + Pb2+

Pb is anode
and Ag is cathode

e- go toward Ag.


Zn + Ni2+ ⇔ Zn2+ + Ni

Zn is anode
and Ni is cathode

e- go toward Ni.
Is this correct?

Thanks.
 
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Unfortunately, you got them backwards in both cases.

Remember reduction (increase in number of electrons) occurs at the cathode while oxidation occurs at the anode. So check which of the elements is more electropositive. That element will form your anode. The periodic table will help you.
 
I don't understand, i used the same method for other problems and I got right answer.
This is what I did.
because for Pb/Pb2+ and Ag/Ag+
the standard reduction at 25 C

Pb2+ + 2e-⇔Pb(s) E = -0.13
Ag++e-⇔Ag(s) E = 0.80

So flip top eq to get an oxidation of Pb and Ag is already in reduction form
so ox = anode
and red = cathode?

so total E = 0.80 + 0.13 = 0.93

thanks for your time.
 
qpham26 said:
2Ag2+ + Pb ⇔ 2Ag + Pb2+

Almost correct. Ag is not 2+, but I assume it is just a typo.

Zn + Ni2+ ⇔ Zn2+ + Ni

Correct.

Although you should use → in both cases.
 
Borek said:
Almost correct. Ag is not 2+, but I assume it is just a typo.



Correct.

Although you should use → in both cases.

Yes it was a typo.
And since it is correct we can see that
Pb lost electron so it is the anode?

same goes for the other case.
 

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