Quick question on notation of the Hamiltonian

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In the discussion about Hamiltonian notation, the upper zero in H^{(0)} indicates the unperturbed Hamiltonian in the context of degenerate perturbation theory. The lower zero in H_{0} denotes the free Hamiltonian, which is combined with a potential interaction part (V) to form the full Hamiltonian. The equations presented illustrate how the Hamiltonian operates on degenerate states, yielding the same energy eigenvalue E_{0}. This clarification helps in understanding the distinctions between different Hamiltonian representations. The conversation effectively resolves the confusion regarding the notation used in quantum mechanics.
rwooduk
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for a degnerate system it's in my notes that you can write:

H^{(0)}\Psi _{1}=E_{0}\Psi _{1}
H^{(0)}\Psi _{2}=E_{0}\Psi _{2}

and (not related) we write the general Schrodinger equation

H_{0}\Psi + V\Psi = E\Psi

Please could someone tell me what both the upper and lower zeros on the H mean?

Thanks in advance
 
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For the "upper zeroes", it seems to me its in the context of degenerate perturbation theory. Then that zero means its the unperturbed Hamiltonian.
For the "lower zero", the full Hamiltonian is written as the free Hamiltonian(H_0) plus a potential(interaction) part (V).
 
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Shyan said:
For the "upper zeroes", it seems to me its in the context of degenerate perturbation theory. Then that zero means its the unperturbed Hamiltonian.
For the "lower zero", the full Hamiltonian is written as the free Hamiltonian(H_0) plus a potential(interaction) part (V).

Great thanks for clearing this up!
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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