What Are the Max and Min Values of the Function f(x) = 1/3X^3 - 1/2^2 - 6x + 4?

[physicszman]

consider function f(x) = 1/3X^3 - 1/2^2 - 6x + 4

maximum is positive infinity and minimum is negative infiniti correct?

Thank you!

 

[matt grime]

Not if you are looking for local optima. It might be better to say there is no global maximum or minimum, than it is at infinity, to avoid unnecessary use of infinity.

 

[HallsofIvy]

Originally posted by physicszman
consider function f(x) = 1/3X^3 - 1/2^2 - 6x + 4

maximum is positive infinity and minimum is negative infiniti correct?

Thank you!

I wouldn't put it that way. I would say that the function is "unbounded" and has no global maximum or minimum.

 

[physicszman]

thanks for the help!