Radial force on a particle with circular motion

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Homework Help Overview

The problem involves a particle of mass 0.014 kg moving in circular motion with a variable rotational velocity defined as 36 + 5*t rad/s. The questions posed include determining the number of revolutions the particle makes in 4.8 seconds, calculating the radial force at that time, and finding the absolute magnitude of the total force acting on the particle.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate the number of revolutions by integrating the rotational velocity over time, resulting in a total of 36.69 revolutions. They also calculate the radial force using the radial acceleration formula but express uncertainty about the correctness of their approach. Other participants suggest considering the direction of the radial force and question the implications of the hint regarding directions.

Discussion Status

Participants are actively discussing the calculations and interpretations of the problem. Some guidance has been offered regarding the potential need to consider the direction of the radial force, although there is no explicit consensus on what is required for the answer.

Contextual Notes

The problem does not provide a starting position for the particle, which raises questions about how to determine the direction of the radial force at the specified time.

Lee333
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A particle of mass 0.014 kg is traveling on a radius 0.9m at a rotational velocity of 36+5*t rad.s-1.


How many revolutions does the particle go thorugh in 4.8 seconds? [revs]


What is the radial force on the particle at 4.8 seconds? [N] (Hint: consider directions)
(question I'm stuck on)


What is the absolute magnitude of force on the particle at 4.8 seconds? [N]



We know that the radial acceleration = v^2/r



To find the amount of revolutions I simply integrated the rotational velocity with respect to time, and found that the particle rotated 230.4 radians or 36.69 revs.

The second question is the question that I seem to be getting wrong. The way I tried to solve it was by firstly finding the rotational velocity after 4.8 seconds:
w = 36+5*4.8
= 60 rad/s

thus we know that the translational velocity is:
v= rw
= 60*0.9
= 54 m/s

we know that the radial acceleration, ra, can be defined by:
ra = v^2/r
= 54^2/0.9
= 3240

thus the radial force, Fr, is:
Fr = m*ra
=0.014*3240
=45.36 N

the above question i am getting wrong for some reason. any help would be appreciated




For the final question we know that the angular acceleration is 5 rad/s^2
this means the linear acceleration of the particle is 4.5 m/s.

we know the translational force will be Ft=m*a
Ft = 0.014*4.5
= 0.063

So we can work out the total magnitude of the force like so:
F_tot = sqrt(0.063^2+45.36^2)
= 45.36
 
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hi lee, welcome to physicsforums :)
Your answer looks good to me. Maybe they also wanted the direction of the radial force at that time.
 
Thanks for answering, I think its got something to do with the consider directions hint, but I am not sure what I've done wrong. I don't think they want the direction of the radial force because they didn't give a starting position for the particle, so we don't know the direction of the force.
 
ah, that's true, they don't give the starting position. Then maybe you are meant to give the direction of the radial force, compared to its direction at t=0 ? This is a bit of a stretch, but I can't imagine what else they want for the answer...
 

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