I understand that there is a way to find a basis [tex]\{e_1,...,e_n\}[/tex] of a vector space [tex] V[/tex] such that a 2-vector [tex] A [/tex] can be expressed as(adsbygoogle = window.adsbygoogle || []).push({});

[tex] A = e_1\wedge e_2 + e_3\wedge e_4 + ...+e_{2r-1}\wedge e_{2r}[/tex]

where 2r is denoted as the rank of [tex]A[/tex]. However the way that I know to prove this seems sort of inelegant. I'm wondering what other proofs people have.

**Physics Forums | Science Articles, Homework Help, Discussion**

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Rank of a 2-vector (exterior algebra)

Loading...

Similar Threads for Rank vector exterior |
---|

I Z2 graded vector space |

Vectors symbol |

I Geometric intuition of a rank formula |

I Can a shear operation introduce a new linear dependency? |

**Physics Forums | Science Articles, Homework Help, Discussion**