jojo12345
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I understand that there is a way to find a basis [tex]\{e_1,...,e_n\}[/tex] of a vector space [tex]V[/tex] such that a 2-vector [tex]A[/tex] can be expressed as
[tex]A = e_1\wedge e_2 + e_3\wedge e_4 + ...+e_{2r-1}\wedge e_{2r}[/tex]
where 2r is denoted as the rank of [tex]A[/tex]. However the way that I know to prove this seems sort of inelegant. I'm wondering what other proofs people have.
[tex]A = e_1\wedge e_2 + e_3\wedge e_4 + ...+e_{2r-1}\wedge e_{2r}[/tex]
where 2r is denoted as the rank of [tex]A[/tex]. However the way that I know to prove this seems sort of inelegant. I'm wondering what other proofs people have.