Agent M27
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Homework Statement
So this isn't just one problem but it is a question as to why it is done one way for two instances and then the opposite way for a third problem. Here it goes.
1) An unknown gas effuses at a rate that is .462 times that of nitrogen gas (at the same temperature). Calculate the molar mass of the unknown gas in g/mol.
2) Uranium-235 can be separated from U-238 by flourinating the uranium to form UF6 (which is a gas) and then taking advantage of the different effusion rates for compounds containing the two isotopes. Calculate the ratio of effusion rates for 238UF6 and 235UF6.
3) A sample of neon effuses from a container in 76 seconds. The same amount of an unknown noble gas requires 155 seconds. Identify the gas.
Homework Equations
\frac{RateA}{RateB} = \sqrt{\frac{M_B}{M_A}}
Where M = molar mass
The Attempt at a Solution
1) \frac{RateA}{RateB} = .462
MA = \frac{M_B}{(.462)^2}
MA = \frac{28.02}{(.462)^2} = 131g
2) Rate A/ MA = U-238 RateB/ MB = U-235
\frac{RateA}{RateB} = \sqrt{\frac{M_B}{M_A}}
\sqrt{\frac{235.054}{238.051}}= .9934
3) This is the one where I am confused on why it was carried out in the way as follows:
If I was to follow the format as shown above, where rateA is over rateB and then on the other side they switch positions, I arrive at a terribly incorrect answer:
\frac{76s}{155s} = \sqrt{\frac{M_U}{20.18g}}
.2404=\frac{M_U}{20.18}\Rightarrow 4.85g which is the incorrect answer.
The only way I can arrive at the correct answer is when rate A is in the same postion on both sides for example:
\frac{76s}{155s} = \sqrt{\frac{20.18g}{M_U}}
MU = \frac{20.18g}{.2404}\Rightarrow 83.9g
Which points to Krypton and that happens to be the correct answer. I realize this is a long question and I have the answer, but I want to make sure I am not missing something in the formatting and why it appears to change between problems. Thanks in advance.
Joe