Rational Completeing the Square

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ISX
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Homework Statement


Equation x^2 = (5/6)x - 1/6 with two proposed solutions shown below: x = 1/3 and x = 1/2, each marked with a green checkmark.

Homework Equations


Textbook page titled COMPLETING THE SQUARE explaining that adding (b/2)^2 to x^2 + bx gives a perfect square, with the identity x^2 + bx + (b/2)^2 = (x + b/2)^2.


The Attempt at a Solution


Alright so the solution is in the above pic, but I can't get anywhere close. You can see from the green circles that the "squares" aren't matching up. So I'm not sure if I can't multiply fractions anymore or what.
Handwritten whiteboard working completing the square for x^2 = (5/6)x - 1/6: halving 5/6 gives 5/12, squaring gives 25/144, and the right side is circled to show the 25/144 term added to both sides, ending with a green note reading NO MATCH beside (x - 5/6)^2 expanded as x^2 - (5/6)x - (5/6)x + 25/36.
 
ISX said:

Homework Statement


[ IMG]http://i49.tinypic.com/51v52u.jpg[/PLAIN]

Homework Equations


[ IMG]http://i50.tinypic.com/9fxswl.jpg[/PLAIN]

The Attempt at a Solution


Alright so the solution is in the above pic, but I can't get anywhere close. You can see from the green circles that the "squares" aren't matching up. So I'm not sure if I can't multiply fractions anymore or what.
[ IMG]http://i47.tinypic.com/2ivzmoj.jpg[/PLAIN]
Your line

[itex]\displaystyle x^2-\frac{5}{6}x+\frac{25}{144}=-\frac{1}{6}+\frac{25}{144}[/itex]

is correct.

What your last line shows (correctly) is that [itex]\displaystyle \left(x-\frac{5}{6}\right)^2\ne x^2-\frac{5}{6}x+\frac{25}{144}\ .[/itex]

When you square 5/6, you don't get 25/144 .

How did you get 25/144 in the first place? You squared 5/12 not 5/6 .
 
Attachments
  • Handwritten work in red and blue on a whiteboard completing the square for x squared minus five sixths x equals negative one sixth, with the 25/144 term circled and the line marked NO MATCH against the expanded square.
    2ivzmoj.jpg
    31.3 KB · Views: 413
you went from
[itex]x^2 +bx + (\frac{b}{2})^{2}[/itex]
to
[itex](x+b)^{2}[/itex]

and not to

[itex](x+\frac{b}{2})^{2}[/itex]
 
Hellllllll I've been doing it wrong for centuries then. Let's try this again.

Handwritten completing-the-square derivation of x squared = (5/6)x - 1/6, with (5/12) squared = 25/144 added to both sides, giving (x - 5/12) squared = 1/144, and a final line reading Checks Out.


Handwritten solution of (x - 5/12)^2 = 1/144: square root taken, x - 5/12 = 1/12 gives x = 1/2 boxed, and OR x - 5/12 = -1/12 gives x = 1/3 boxed, with AH HA! written below.


Ahhhh! Thanks for the help guys! I was always just dropping the last number off and went with the first 2. Guess I never caught on that fractions didnt work that way.