Rationalizing Denominators: Understanding the Process

  • Thread starter Thread starter majormuss
  • Start date Start date
Click For Summary

Homework Help Overview

The discussion revolves around the process of rationalizing denominators, specifically in the context of an equation involving roots and powers of x. The original poster expresses confusion regarding the use of x^2 for rationalization when the equation involves x^3.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the reasoning behind using x^2 instead of x^3 for rationalization, questioning the necessity of the chosen power. There is a focus on understanding the relationship between the roots and the powers involved.

Discussion Status

Some participants provide insights into the rationale for using specific powers in the rationalization process, suggesting that the goal is to achieve a fifth power inside the fifth root. The conversation indicates a progression towards understanding the underlying principles, though not all questions have been fully resolved.

Contextual Notes

The discussion includes references to general rules for rationalizing denominators involving roots, but there is an emphasis on the specific case at hand, which may not have been fully clarified for all participants.

majormuss
Messages
124
Reaction score
4

Homework Statement



I am confused with this equation I found online... It seems wrong to me, I need help.
My question is,why did the person who worked taht equation use a x^2 to rationalize the equation when the actual equation was an x^3??
http://tutorial.math.lamar.edu/Classes/Alg/Radicals_files/eq0081MP.gif

Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
Because the fifth root of x^2*x^3=x^5 is x. How would you do it??
 
Dick said:
Because the fifth root of x^2*x^3=x^5 is x. How would you do it??

no my question is... why was x^2 used instead of x^3 to rationalize the denominator? my thinking is if x^2 is the denominator then why use x^3 to rationalize it?
 
Because [itex]x^2*x^3= x^5[/itex] as Dick said. The crucial point is that it is the fifth root that is to be rationalized. You have to multiply what ever power is necessary to get a fifth power inside the fifth root.

In general to rationalize the denominator of [itex]1/\sqrt[n]{x^m}[/itex] you need to multiply numerator and denominator by [itex]\sqrt[n]{x^{n-m}}[/itex]. That way, in the denominator you will have [itex]\sqrt[n]{x^nx^{n-m}}= \sqrt[n]{x^n}= x[/itex].
 
HallsofIvy said:
Because [itex]x^2*x^3= x^5[/itex] as Dick said. The crucial point is that it is the fifth root that is to be rationalized. You have to multiply what ever power is necessary to get a fifth power inside the fifth root.

In general to rationalize the denominator of [itex]1/\sqrt[n]{x^m}[/itex] you need to multiply numerator and denominator by [itex]\sqrt[n]{x^{n-m}}[/itex]. That way, in the denominator you will have [itex]\sqrt[n]{x^nx^{n-m}}= \sqrt[n]{x^n}= x[/itex].

I get it now thanks..
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
12
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 19 ·
Replies
19
Views
3K